Transmission line approimation

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 3K views
likephysics
Messages
638
Reaction score
4
Transmission line approximation

Homework Statement


In the derivation of the approximate formulas of \gamma and Z0 for low loss lines, all terms containing the second and higher order powers of R/wL and G/wC were neglected in comparison with unity. (R/wL<<1 and G/wC<<1)
gamma=jw*sqrt(LC)*sqrt(1+R/jwL)*sqrt (1+G/jwC)
approximated to
gamma = jw*sqrt(LC)*(1+R/2jwL)*sqrt(1+G/2jwC)

gamma is the propagation constant which is equal to alpha+j beta

At lower frequencies, better approximation may be required. find new formulas for \gamma and Z0 for low loss lines that retain terms containing (R/wL)^2 and (G/wL)^2


Homework Equations


Required result is
alpha = sqrt(LC/2)*(R/L+G/C)*[1-(1/8w^2)*(R/L-G/C)^2]
beta = w*sqrt (LC)*[1+(1/8w^2)*(R/L-G/C)^2]


The Attempt at a Solution


I tried expanding the term
sqrt(1+R/jwL) using square root expansion :
1+(1/2)*R/jwL-(1/8)*(R/jwL)^2
did the same for sqrt (1+G/jwC)
I am unable to get the desired result. Any help.
FYI, this is prob 9.7 in cheng.
 
Last edited:
Physics news on Phys.org


likephysics said:
I tried expanding the term
sqrt(1+R/jwL) using square root expansion :
1+(1/2)*R/jwL-(1/8)*(R/jwL)^2
did the same for sqrt (1+G/jwC)

That looks fine to me...what do you get when you multiply everything out?