Transverse wave equation period

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SUMMARY

The transverse wave equation provided is y(x, t) = (0.750 cm) cos(π[(0.400 cm-1)x + (250 s-1)t]). To find the period, the equation must be rewritten in standard form as y(x, t) = A cos[2π(x/λ + t/T)]. By comparing the coefficients, it is established that the angular frequency ω = 250 s-1 leads to a period T = 2π/ω, resulting in T = 0.025 s.

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james brug
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A transverse wave on a rope is given by [tex]y(x, t)=<br /> (0.750\; {\rm cm})\, \cos ( \, \pi [(0.400\;{\rm cm}^{ - 1})x+(250\; {\rm s}^{ - 1})t])[/tex]


Find the period.

This should be simple, but I keep getting the wrong answer in Mastering Physics. I can't find any explanation in my book, and it's really irritating me.
 
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Rewrite the equation in a standard form.
y(x,t) = Acos[2*pi(x/lambda + t/T)]
Compare this with the given equation and find the period.
 

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