Triangle Inequalities Relationship

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ait.abd
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I know the following
[tex]|x|-|y| \leq |x+y| \leq |x| + |y|[/tex]
where does [tex]|x-y|[/tex] fit in the above equation?
 
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How about [itex]x+(-y)[/itex]?

also, notice that there is a sort of better result, but I like the way you wrote it, makes it easier to remember and figure out what might be needed in a problem. But sometimes the left inequality is written:

[itex]||x|-|y||\le|x+y|[/itex]

Just so that you understand when many other people write this.
 
algebrat said:
How about [itex]x+(-y)[/itex]?

also, notice that there is a sort of better result, but I like the way you wrote it, makes it easier to remember and figure out what might be needed in a problem. But sometimes the left inequality is written:

[itex]||x|-|y||\le|x+y|[/itex]

Just so that you understand when many other people write this.

So

[itex]|x|-|y| \leq |x+y| \leq |x| + |y|[/itex]

and

[itex]|x|-|y| \leq |x-y| \leq |x| + |y|.[/itex]

I think we can't say anything about the relationship between[itex]|x+y|[/itex] and [itex]|x-y|,[/itex]
and in between [itex]||x|-|y||[/itex]and [itex]|x|-|y|.[/itex]
 
[itex]|x+y|\ge||x|-|y||\ge|x|-|y|[/itex]
 
ait.abd said:
I think we can't say anything about the relationship between[itex]|x+y|[/itex] and [itex]|x-y|,[/itex]

You can prove this pretty quickly by plugging numbers in, or just notice that the replacement ##y \mapsto -y## yields the other, hence the only possible relation is equality, which is clearly false.
 
ait.abd said:
I think we can't say anything about the relationship between[itex]|x+y|[/itex] and [itex]|x-y|,[/itex]
and in between [itex]||x|-|y||[/itex]and [itex]|x|-|y|.[/itex]

if x and y have like signs then lx+yl ≥ lx-yl if unlike signs then lx+yl≤ lx-yl , check it out and always llxl-lyll >= lxl-lyl