Can a 63mm Bore Pneumatic Ram handle the required weight at an angled position?

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SUMMARY

The discussion centers on calculating the weight capacity of a 63mm Bore Pneumatic Ram when positioned at an angle. The user is familiar with vertical calculations but struggles with angled scenarios, requiring assistance in vector decomposition. Key concepts include the use of trigonometric functions such as sine and cosine to resolve forces into vertical and horizontal components. The principle of virtual work is also suggested as a relevant approach to solving the problem.

PREREQUISITES
  • Understanding of basic physics principles, particularly force vectors
  • Knowledge of trigonometry, specifically sine and cosine functions
  • Familiarity with the principle of virtual work
  • Ability to create and interpret force diagrams
NEXT STEPS
  • Study vector decomposition in physics
  • Learn how to apply trigonometric functions in force calculations
  • Research the principle of virtual work and its applications
  • Practice creating detailed force diagrams for various scenarios
USEFUL FOR

Students in physics, engineers working with pneumatic systems, and anyone involved in mechanical design requiring force analysis at angles.

AnnekeL
Hey

So I am still a beginner in Physics and work asked me today to calculate if a 63mm Bore Pneumatic Ram will do the required job. Anyway, so I know how to calculate the weight capacity the ram can handle if it is at a 90 deg angle however if the ram is on an angle then I am stuck. I need to get back to them today and as a part student, I am finding this hard. any help would be awesome :)

I have attached a sketch of the layout and how i calculate the weight capacity calculations i have done.
 

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AnnekeL said:
Anyway, so I know how to calculate the weight capacity the ram can handle if it is at a 90 deg angle however if the ram is on an angle then I am stuck.
Force is a vector. Do you know how to write a vector as a sum of components?
 
You meaning like a resultant force where Fnet=F1+F2?
 
AnnekeL said:
You meaning like a resultant force where Fnet=F1+F2?
Sort of, but working backwards in this case: you know the total force already and you need to write it as the sum F1 and F2, where one of these is vertical and one is horizontal. You'll need some basic trigonometry (what ##\sin## and ##\cos## mean) as well.
 
In your diagram what is fixed and what is moving and in which directions ?

If you can describe the problem more completely I'm sure we can help you solve it . A realistic pictorial sketch would be very useful .
 
Last edited:
As an old man, I'd like to second Nidum's request, and add that the figure needs to be more sharp with darker lines.

From the little I could see, this looks like a prime application for the principle of virtual work.
 

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