(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A block with mass m =6.7 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.26 m. While at this equilibrium position, the mass is then given an initial push downward at v = 4.7 m/s. The block oscillates on the spring without friction.

3)After t = 0.4 s what is the speed of the block?

4)What is the magnitude of the maximum acceleration of the block?

Calculated K = 252.5384615

Oscillation Frequency (omega) = .9771168341

2. Relevant equations

Amplitude = vMax*sqrt(m/k)

3. The attempt at a solution

I got amplitude to be 0.7655.

I used -(omega)*Acos(omega*t) to find V for number 3. I used aMax = omega^2*t

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# Homework Help: Tricky spring problem. Amplitudes and AccelerationMax

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