A block with mass m =6.7 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.26 m. While at this equilibrium position, the mass is then given an initial push downward at v = 4.7 m/s. The block oscillates on the spring without friction.
3)After t = 0.4 s what is the speed of the block?
4)What is the magnitude of the maximum acceleration of the block?
Calculated K = 252.5384615
Oscillation Frequency (omega) = .9771168341
Amplitude = vMax*sqrt(m/k)
The Attempt at a Solution
I got amplitude to be 0.7655.
I used -(omega)*Acos(omega*t) to find V for number 3. I used aMax = omega^2*t