Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Tricky spring problem. Amplitudes and AccelerationMax

  1. Nov 21, 2011 #1
    1. The problem statement, all variables and given/known data

    A block with mass m =6.7 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.26 m. While at this equilibrium position, the mass is then given an initial push downward at v = 4.7 m/s. The block oscillates on the spring without friction.

    3)After t = 0.4 s what is the speed of the block?
    4)What is the magnitude of the maximum acceleration of the block?

    Calculated K = 252.5384615
    Oscillation Frequency (omega) = .9771168341

    2. Relevant equations

    Amplitude = vMax*sqrt(m/k)

    3. The attempt at a solution
    I got amplitude to be 0.7655.
    I used -(omega)*Acos(omega*t) to find V for number 3. I used aMax = omega^2*t
  2. jcsd
  3. Nov 22, 2011 #2
    I believe there is an equation that you use to find the velocity at any given point given amplitude, stretched distance, k and mass. hold on.... so its the sqrt(k/m) times the sqrt(amplitude^2 - stretched or compressed distance^2) use that
  4. Nov 22, 2011 #3
    oh nevemind. use 9.8m/s^2(t) to find the speed after sometime. isnt the acceleration the same?
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook