Trig - Double Angles Questions,

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Homework Help Overview

The discussion revolves around double angle identities in trigonometry, specifically focusing on the correct formulations and interpretations of these identities.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are examining the validity of the double angle identities presented, with some questioning the accuracy of the original poster's claims and others defending the identities as equivalent.

Discussion Status

The conversation is active, with participants engaging in a back-and-forth regarding the correctness of the double angle identities. There is no clear consensus, but the discussion is focused on clarifying misunderstandings and verifying the identities.

Contextual Notes

Some participants express uncertainty about the correctness of the identities and the signs used in the equations, indicating a need for further verification and discussion.

Macleef
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Trig - Double Angles Questions, Please Help!

please close, solved all my problems myself...
 
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Double Angle Identities are as follows:
sin2x = 2sinxcosx

cos2x = cos^2x - sin^2x
= 2sin^2x - 1
= 2cos^2x - 1
first off, your double-angle identities are wrong

[tex]\cos{2x}=\cos^{2}x-\sin^{2}x[/tex]

[tex]\cos{2x}=2\cos^{2}x-1[/tex]

[tex]\cos{2x}=1-2\sin^{2}x[/tex]
 
rocophysics said:
first off, your double-angle identities are wrong

[tex]\cos{2x}=\cos^{2}x-\sin^{2}x[/tex]

[tex]\cos{2x}=2\cos^{2}x-1[/tex]

[tex]\cos{2x}=1-2\sin^{2}x[/tex]

what are you talking about? they're exactly the same
 
Macleef said:
what are you talking about? they're exactly the same
your signs are off, i haven't checked your work though
 

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