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Homework Statement
An object has a weight of 20N. It is supported by three strings to keep it in equilibrium, all attached to a smooth ring on the object. String A has a tension of 15N to the right of the block. String B is (a)degrees away from string A and String C is 90degrees away from String B. String B and C have the same tension. Show that the angle is 82 degrees
Homework Equations
cos(theta)/sin(theta)=tan(theta)
Forces in equilibrium cancel each other out.
The Attempt at a Solution
So far I've got this, but get stuck past this point:
15+Bcos(a)=Acos(90-a) and 20=Bsin(a) + Asin(90-a)
A and B then can be replaced by T and rearranged:
Tcos(a)=-Tsin(90-a) + 20
Tsin(a)= Tcos(90-a)-15
tan(a)= -Tsin(90-a)+20/Tcos(90-a)-15
But then I don't know how to resolve it. Any help at all would be greatly appreciated! Many Thanks!