(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A fire hose held near the ground shoots water at a speed of 6.8m/s. At what angle(s) should the nozzle point in order that the water land 2.0m away? Why are there two different angles?

2. Relevant equations

v = v(initial) +at

x = x(initial) + v(initial)t + .5at^2

v^2 = v^2(initial) + 2a(x - x(initial)

x=vt

3. The attempt at a solution

I first drew a right triangle and by the problem i was only given the hypotenuse (6.8). Knowing that the adjacent line is the initial velocity in the positive x direction and that the opposite line is the initial velocity in the y positive direction, i tried to solve for theata that way.

So I did:

Initial Velocity in the positive X direction is:

X= X(initial) + V(initial)(t) + .5(a)(t^2)

2= 0 + (6.8)(cos theta)(t) + 0

2= (6.8)(cos theata)(t)

Initial velocity in the positive Y direction is:

Y= Y(initial) + V(initial)(t) + .5(a)(t^2)

0= 0 + (6.8)(sin theta)(t) + (-4.9)t^2

0= (6.8)(sin theta)(t) + (-4.9)t^2

Once I got to this point I had no idea what to do... any guidance from here would be greatly appreciated. I've never taken Physics before and took geometry around 10 years ago so this has all been erased from my memory..

Thanks

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Projectile Motion Angles Question

**Physics Forums | Science Articles, Homework Help, Discussion**