Trigonometric Identities and equations

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SUMMARY

The discussion focuses on solving the trigonometric equation 5(sin x - cos x) = 4sin x - 3cos x within the domain 0° < x < 360°. The equation simplifies to sin x - 2cos x = 0, leading to the conclusion that sin x = 2cos x. The solution involves identifying the basic angle and determining the quadrants where the equation holds true. The participants successfully navigate through the algebraic manipulation to arrive at the solution.

PREREQUISITES
  • Understanding of trigonometric identities such as sin^2 x + cos^2 x = 1
  • Familiarity with solving equations involving sine and cosine functions
  • Knowledge of the unit circle and angle quadrants
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Learn how to derive and apply trigonometric identities in problem-solving
  • Study the unit circle to better understand angle measures and their corresponding sine and cosine values
  • Explore the graphical representation of trigonometric functions to visualize solutions
  • Practice solving a variety of trigonometric equations, including those with multiple angles
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone looking to enhance their problem-solving skills in trigonometric equations.

wei1006
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1) Problem statement:
Solve the trigonometric equation for the domain is. 0°<x<360°
5(sinx - cosx) = 4sinx - 3cosx

2) relevant equations:
secx=1/cosx
cosec x=1/sinx
cot x= 1/tanx
tan x=sinx/cosx
cot x=cosx/sinx
sin^2 x + cos^2 x=1
1 + tan^2 x= sec^2 x
1+ cot^2 x = cosec^2 x

Template of answer:
New domain:
Basic angle=
Quadrants=
Solve for x
3)Attempt the question
5(sin x - cosx)=4sinx - 3cosx
5sinx-4sinx-5cosx+3cosx=0
sinx - 2 cos x=0
 
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wei1006 said:
sinx - 2 cos x=0

Fine up to here, so what is the solution to this equation?
 
I am not sure how to continue...
 
How about trying to rewrite it by placing the 2 cos x on the other side and then dividing by something that makes it easier?
 
Thank you for your help, have solved it
 

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