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Trigonometry, find solutions between [0/2pi]

  1. Feb 25, 2009 #1
    1. The problem statement, all variables and given/known data
    solve, finding all solutions between [0,2pi]
    tanx=3cotx

    3. The attempt at a solution

    It looks like a relatively simple problem if one knew what they were doing unfortunately I do not. I am trying to think of this graphically and I figure that the places were tanx=3cotx are where the functions intersect. but how do i figure out the values?
     
  2. jcsd
  3. Feb 25, 2009 #2
    I would think about decomposing tan and cot in their sin & cos components and then work from there. Maybe sin^2(x)+cos^2(x)=1 might be helpful, who knows ;)
     
  4. Feb 25, 2009 #3
    cotx = 1 / tanx
     
  5. Feb 25, 2009 #4
    got it thx
     
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