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## Homework Statement

##tanx=\frac{(1+tan1)(1+tan2)-2}{(1-tan1)(1-tan2)-2}## find x

## Homework Equations

3. The Attempt at a Solution [/B]

I tried multiplying through the paranthesis and arrived at ##tanx=\frac{(tan1tan2-1)+(tan2+tan1)}{(tan1tan2-1)-(tan2+tan1)}## and i dont know if this is any simpler than what was originally set. Is there a trigonometric identity at play here?