Trig Inequalities: Solve tanx - 3cotx = 0 in the Interval [0, 2pi)

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SUMMARY

The equation tanx - 3cotx = 0 is solved in the interval [0, 2pi) by first rewriting it as tanx = 3cotx, leading to the equation tan^2x = 3. The solutions for tanx = sqrt3 are x = pi/3 and x = 7pi/6, while for tanx = -sqrt3, the solutions are x = 2pi/3 and x = 11pi/6. The periodic nature of the tangent function confirms the correctness of these solutions, as they align with the expected reference angles.

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Homework Statement


Solve the following equations or inequalities in the interval [0, 2pi)

tanx - 3cotx = 0


Homework Equations





The Attempt at a Solution



tanx = 3cotx
tanx = 3/tanx
tan2x = 3
tanx = +-sqrt3
tanx = sqrt3 or tanx = -sqrt3

tanx = sqrt3
x = pi/3, 7pi/6

tanx = -sqrt3
x = 2pi/3, 11pi/6

Is this right?
 
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check your answers

tan is periodic with a period of pi, your solutions for a given sign do not have period of pi
 
Both your primary answers to each equation were correct.

But why did you from answers with reference angles of pi/3 to that of pi/6 for your secondary answers?
 

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