Trigonometry with an inclined plane

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bdolle
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<Moderator's note: Moved from a technical forum and therefore no template.>

I don't understand the math here which is troubling considering I got A's in calc 2 and 3...

I tried to divide both sides by cos(theta) and solve for tantheta. but that gives something different.

Also, what does tantheta>=1 even mean? Is this second quadrant or fourth quadrant?

Thanks!
 
Attachments
  • Diagram of a block of mass M on a fixed inclined plane at angle θ, with a horizontal force Mg applied to the block; caption reads Example (Block on a plane) and Fig. 2.1.
    Screen Shot 2017-09-04 at 9.57.28 PM.png
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  • Worked derivation of inequalities involving tan θ and μ, with equations labelled (2.4) and (2.5) and two cases split by the absolute value.
    Screen Shot 2017-09-04 at 9.55.31 PM.png
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Last edited by a moderator:
Nevermind. Got the equation for the tan>1 case (I was thinking tan>0 or tan<0 not 1).

But for the case where tan of theta is less than one, that would mean between pi/4 and pi/2. I'm wondering why sintheta becomes negative and costheta becomes positive.

Any takers?
 
bdolle said:
where tan of theta is less than one, that would mean between pi/4 and pi/2.
Between -π/2 and π/4.