Troubleshooting Steam Plant Output: Tips for Evening Class Assignment

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Homework Help Overview

The discussion revolves around troubleshooting a problem related to calculating steam output in a steam plant context, specifically focusing on the efficiency of the system and the relevant formulas involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for calculating steam output, questioning the rearrangement of the formula and the application of overall system efficiency. There is uncertainty about whether to include certain components like the economizer and super heater in the calculations.

Discussion Status

Some participants have offered guidance on using the overall efficiency directly in calculations, while others are still clarifying the steps and confirming the correctness of the approach. Multiple interpretations of the problem setup are being explored.

Contextual Notes

There is mention of a specific efficiency value (77%) and a formula (Q=M(h2-h1)), but the context of the problem and any additional constraints or assumptions are not fully detailed.

anthonyk2013
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Im attempting this question for an evening class I am attending. hope I am posting in the right place. I'm not sure where I have gone wrong think its where I rearranged my formula to find steam output.

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The work is a bit unclear. I'll get back to you in a day or so.
 
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Ok Thanks
 
I think I calculated the steam output wrong, I have the over all efficiently of the system 77%, what formula do I use the calculate steam output?
Q=M(h2-h1)
 
Yeah that's the one..!
For calculating the steam output, you can directly use the 77% efficiency without involving the economizer and super heater (if I'm not wrong).
So 77% of the heat obtained from the combustion of coal is used to convert water to steam.
 
siddharth23 said:
Yeah that's the one..!
For calculating the steam output, you can directly use the 77% efficiency without involving the economizer and super heater (if I'm not wrong).
So 77% of the heat obtained from the combustion of coal is used to convert water to steam.

77% is the overall efficiency am I right ? So did I divide .77 by h2-h1 to get steam output?
 
anthonyk2013 said:
77% is the overall efficiency am I right ? So did I divide .77 by h2-h1 to get steam output?
Yes! And equate it with the energy provided by the combustion of coal. Tell me if that gives the right answer.
 
6244.09 kg/h
 
I meant did you get the right answer?
 

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