Troubleshooting Tension: A Closer Look at Rotational Motion Calculations

Click For Summary

Homework Help Overview

The discussion revolves around a problem related to rotational motion and tension in a system involving a compound pulley and attached masses. Participants are examining the relationship between angular acceleration, radius, and the forces acting on the system.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning why the radius used in calculations should be the axle radius instead of the wheel radius, despite the problem stating it concerns the wheel's angular acceleration. There are discussions about the relationship between linear and angular acceleration and the significance of the attachment point of the rope.

Discussion Status

Some participants have provided guidance on using the correct radius for calculations based on where the rope attaches. There is an ongoing exploration of the implications of using different radii and how they affect the calculations. The conversation is productive, with participants clarifying concepts and addressing misunderstandings.

Contextual Notes

Participants are navigating through the constraints of the problem, including the need to relate linear and angular quantities and the definitions of forces acting on the system. There is a mention of multiple unknowns in the equations, which adds complexity to the discussion.

freshbox
Messages
290
Reaction score
0

Homework Statement


The tension answer I got is different from the answer. Can someone help me take a look at my working? Really appreciate your time in doing this. Thanks a lot.
 

Attachments

  • fbd.jpg
    fbd.jpg
    12.5 KB · Views: 516
  • myworking.jpg
    myworking.jpg
    22.7 KB · Views: 535
  • question.jpg
    question.jpg
    42 KB · Views: 466
Physics news on Phys.org
And if my answer is right... I want to ask the question states that "Angular acceleration compound pulley B is 5rad/s^2"

From this statement, why my radius is not the wheel radius (0.1) but I have to use the axle radius?

The whole wheel B is pulling mass A. shouldn't I use the wheel radius instead of the axle to find the acceleration?

More support to my statement: Wheel B And Parcel = Linear variables same. So all the more I should use Wheel radius to find acceleration.
 
Last edited:
Yes, you should use the radius 0.1 because that's where the rope pulling A attaches.
 
Yea you are right, I sub in the values and got the exact answer.

Can I say for such questions to find acceleration, always use the radius that the rope is attaching to?
 
freshbox said:
Can I say for such questions to find acceleration, always use the radius that the rope is attaching to?
When you want the acceleration of the rope (which is the acceleration of the attached mass) then you want to use the radius where the rope attaches.
 
With regards to this attached question. They are asking me to "calculate the angular acceleration produced on the wheel"

Why can't i take the wheel radius since the question says "acceleration produced on the wheel" ?
 

Attachments

  • quest.jpg
    quest.jpg
    39.8 KB · Views: 495
freshbox said:
Why can't i take the wheel radius since the question says "acceleration produced on the wheel" ?
Not sure what you mean. The angular acceleration is the same at any radius. (Don't confuse angular with linear acceleration.)

There are two forces of interest acting on the wheel. The torque produced by each force depends on where it is applied--that's the radius you'd use to calculate the torque.
 
From Equation 3, how come I need to use the axle radius but not the wheel radius, since the question is asking me to find the angular acceleration of the wheel.
 

Attachments

  • work.jpg
    work.jpg
    24.9 KB · Views: 523
freshbox said:
From Equation 3, how come I need to use the axle radius but not the wheel radius, since the question is asking me to find the angular acceleration of the wheel.
Again, do not confuse angular acceleration of the assembly, which is the same for wheel and axle, with the linear (or tangential) acceleration of some part of the wheel, which depends on the radius at that point.

In Equation 3, you are relating the linear acceleration a from Equation 2 to the angular acceleration. The linear acceleration is the acceleration of the rope and hanging mass. Where is the rope attached?
 
  • #10
rope is attached to the axle.
 
Last edited:
  • #11
freshbox said:
rope is attached to the axle.
Right. Thus to relate the linear acceleration of the rope (and thus the hanging mass) to the angular acceleration, you'll use the radius of the axle.
 
  • #12
Does the wheel turn anticlockwise(because force 50N is pushing) and axle turning clockwise because Box A is pulling it down. Both turning different direction or the Wheel+Axle is turning together?
 
  • #13
freshbox said:
Does the wheel turn anticlockwise(because force 50N is pushing) and axle turning clockwise because Box A is pulling it down. Both turning different direction or the Wheel+Axle is turning together?
The wheel + axle is a single connected assembly. It turns as one unit. (Thus wheel and axle have the same angular acceleration.)
 
  • #14
Ok i understand it already, thanks a lot. Doc Al I have 1 last question, can you help me take a look.

I managed to find all the answers except for part E.

This is part of the working. My equation for FBD of Box C is as follow:

Summation Fy=ma
Tc-Wc=Mca

I have values for Tc, a, after subbing it in I have.
147.945-Wc=Mc(0.13)
I left 2 unknown which I am unable to continue.

I have look through the working from the FBD of Wheel and Box A but I cannot try to form an equation to find either Mc or Wc, can you guide me please. Thanks.
 

Attachments

  • a.jpg
    a.jpg
    75.6 KB · Views: 485
  • #15
freshbox said:
I have values for Tc, a, after subbing it in I have.
147.945-Wc=Mc(0.13)
I left 2 unknown which I am unable to continue.
You really only have one unknown. How are weight and mass related?
 
  • #16
Weight = mass x 9.81

mass = Weight / 9.81
 
Last edited:
  • #17
freshbox said:
Weight = mass x 9.81

mass = Weight / 9.81
Right! Weight = mass X g.

So now you can solve for the mass of C.
 
  • #18
Ahh... I got it already, thanks for the guidance and your time :biggrin:
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 60 ·
3
Replies
60
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
13
Views
2K