(True/False) Basic Probability Theory

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Discussion Overview

The discussion revolves around the interpretation of basic probability theory, specifically concerning the probabilities of events defined by the outcomes of tossing a fair coin. Participants explore the validity of a statement regarding the probabilities of events X, Y, and Z, which represent different outcomes of heads in a series of coin tosses.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Rela questions the validity of the statement P(Z)=P(X+Y)=P(600)=P(200+400)=P(X)+P(Y)=P(200)+P(400) and seeks clarification on why it is considered false.
  • Tim explains that P(Z) represents the probability of obtaining exactly 600 heads and questions the meaningfulness of the statement regarding the union of events.
  • Rela expresses confusion about the application of the rule for the union of two events, P(A U B) = P(A) + P(B), and seeks further clarification on its correct application.
  • Tim reiterates that the rule applies only to distinct, non-overlapping events and suggests that X and Y are distinct while Z represents their union.

Areas of Agreement / Disagreement

Participants express differing views on the meaningfulness of the original probability statement, with some considering it meaningless while others attempt to apply probability rules to it. The discussion remains unresolved regarding the validity of the initial claim.

Contextual Notes

Participants highlight the importance of distinguishing between overlapping and non-overlapping events when applying probability rules, but the specific conditions under which the original statement holds true are not fully clarified.

rela
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Dear all,

I have a question.

Suppose we have 3 events X,Y,Z defined as having 200 heads, 400 heads & 600 heads obtained in tossing a fair coin for 800 times.

Then, P(Z)=P(X+Y)=P(600)=P(200+400)=P(X)+P(Y)=P(200)+P(400)

The answer is false but I view it otherwise. My argument is based on the idea of the union of 2 events -> P(X U Y) =P(X) + P(Y). Following this line of reasoning, why is the above statement not considered true?

Please kindly elaborate and direct me to the right understanding level.

Thanks in advance.

Regards
Rela
 
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Hi Rela! :smile:

P(Z) is the probability of exactly 600 heads …

in full, P(Z) = P({600 heads and 200 tails}) …

so is the statement P({600 heads and 200 tails}) = P({400 heads and 400 tails} U {200 heads and 600 tails}) true or false or meaningless? :wink:
 
Hi Tim,

Many thanks for your prompt revert.

Hmmm...It looks kinda meaningless to me. But I'm just perturbed by the fact that there exists such a rule in which the probability of the union of 2 statistically events A & B is the the sum of their individual probabilities (i.e P(AUB)=P(A)+P(B).

I just feel that I could apply this rule to the problem statement defined earlier since it makes sense mathematically.

Are you able to elaborate more on the circumstance in which I could apply the above rule correctly then?

Regards
Rela
 
Hi Rela! :smile:
rela said:
Hmmm...It looks kinda meaningless to me.

Yes, that's right … it's meaningless! :biggrin:
But I'm just perturbed by the fact that there exists such a rule in which the probability of the union of 2 statistically events A & B is the the sum of their individual probabilities (i.e P(AUB)=P(A)+P(B).

The probability of the union of 2 distinct (non-overlappping) events A & B is the the sum of their individual probabilities.

(and the probability of the intersection of 2 independent events A & B is the the product of their individual probabilities :wink:)
I just feel that I could apply this rule to the problem statement defined earlier since it makes sense mathematically.

Are you able to elaborate more on the circumstance in which I could apply the above rule correctly then?

yes … you could use the rule if X is exactly 200 heads, Y is exactly 400 heads, and Z is exactly either 200 or 400 heads. :smile:

(because X and Y are distinct … ie, they don't overlap … and Z is their union)
 

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