True/false examinations by tossing a coin

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2.) A student selects his answers on a true/false examinations by tossing a coin (so that any particular answer has a 0.50 probability of being correct). He must answer at least 70% in order to pass. Find the probability of passing when the number of questions is:
(a) 10 (b) 20 (c) 50 (d) 100

EDIT: None of that multiplication rule crap should apply here, D'OH!

I think this too is another case of the binomial probability; hence:

[tex]X \sim Bin(10,0.5)[/tex]

I must evaluate the cases where,

n=10,20,50,100

Ah! The 70% comes into play for the probability. I want probability of greater than 70%, or for values of [tex]X \geq .7n[/tex]

Problem a.)

From the table,

[tex]P(X \geq 7) = 1- 0.945[/tex]

So,

[tex]P(X \geq 7) =[/tex]5.5%

Not good chances!

Part b.)

[tex]P(X \geq 14) = 1- 0.979[/tex]

[tex]P(X \geq 7) =[/tex]2.1%

Part c.)

[tex]P(X \geq 35) = 1- 0.99870[/tex]

[tex]P(X \geq 7) =[/tex]0.13%

Part d.)

[tex]P(X \geq 70) = 1- 1[/tex]

I begrudgingly made a quick for loop in MATLAB to calculate Binomial probability values as high as n=100, with x =70 and p =.5, It spat out 1.000. So,

The probability of getting a 70% and up is 1-1=0. You ant gota chance.

My advice, don't guess on your exams, always cheat.
 
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But if you always cheat you will eventually get caught! :)

Here's an auxiliary problem for you. If the probability of getting caught cheating on any given day is 1 in 100, what is the probability that you will be caught cheating over the course of, say, the next 2 years? The next 5 years? The next 10 years?
 
NOOO! I seriously have TONS and TONS of stat HW due tomorrow and I am trying to learn as I go because my teacher is terrible :mad: I think I am going to get a 3/7 on my HW if I am LUCKY. Are my answers right?