MHB Truth Table Precedence: Evaluating Implication Rules

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The discussion centers on the precedence of the implication operator "⇒" in truth tables, specifically whether to evaluate expressions like P⇒(Q⇒R) or (P⇒(Q⇒R))⇒((P⇒Q)⇒R). Participants clarify that "⇒" has right-to-left precedence, leading to the conclusion that the correct evaluation should be (P⇒(Q⇒R))⇒((P⇒Q)⇒R). It is noted that while some textbooks treat implication as left-associative, the convention in this context is right-associative. Additionally, there is a discussion about the different symbols for implication, with the understanding that notation can vary by source. The conversation concludes with a confirmation that the expression in question is not a tautology.
lyd123
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Hello!
The question is attached.

I know that " $\implies $ " (implies) has precedence from right to left. But because " l- " appears after
P$\implies ($Q $\implies$ R ), in my truth table do I evaluate:(P$\implies ($Q $\implies$ R ) ) $\implies$ ((P$\implies$Q ) $\implies$ R ) )
or

P$\implies ($Q $\implies$ R ) $\implies$ (P$\implies$Q ) $\implies$ R )

Thank you for any help. :)
 

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The turnstile separates formulas but is not a logical connective itself. Therefore $$A\vdash B$$ is equivalent to the fact that $$A\to B$$ is a tautology. This formula has $A$ and $B$ as subformulas joined by $\to$, but it cannot have a subformula that consists of a strict subformula of $A$ and $B$, for example. So it's wrong to consider $P\to(Q\to R)\to(P\to Q)\to R$, which is $P\to((Q\to R)\to((P\to Q)\to R))$ because it has a subformula $(Q\to R)\to((P\to Q)\to R)$, which consists of a part of $A$ and the whole $B$.

lyd123 said:
I know that " $\implies $ " (implies) has precedence from right to left.
I also like this convention, but I've seen textbooks that consider $\to$ to be left-associative, so one has to be careful.
 
I think I understand now.. so I should use (P⟹(Q ⟹ R ) ) ⟹ ((P⟹Q ) ⟹ R ) ),
which would give me the attached truth table.
View attachment 8719

So it is not a tautology. Is this correct?
 

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Yes, it is correct. The converse implication is a tautology. This follows from the fact that $P\to Q\to R$ is equivalent to $PQ\to R$ (I omitted conjunction) and $PQ$ implies $P\to Q$.

There is a typo in column R, second last row.
 
Just a quick question from a novice.

Do [math]\implies[/math] and [math]\rightarrow[/math] mean the same thing? I note that the OP and Evgeny.Makarov are using two different symbols.

-Dan
 
topsquark said:
Do [math]\implies[/math] and [math]\rightarrow[/math] mean the same thing? I note that the OP and Evgeny.Makarov are using two different symbols.
This completely depends on the textbook or other source. Implication can be denoted by $\rightarrow$, $\to$ and $\supset$, and in addition arrows can be short of long. Some authors use different notations for metalevel (a contraction for "if... then..." in English) and object level (a part of the formal language we study) implications. I used a single arrow because it occurs in the attached image in post #1, which I assume comes from the instructor, and because it is shorter in LaTeX ([m]\to[/m] vs [m]\Rightarrow[/m] or [m]\Longrightarrow[/m]).
 
Greetings, I am studying probability theory [non-measure theory] from a textbook. I stumbled to the topic stating that Cauchy Distribution has no moments. It was not proved, and I tried working it via direct calculation of the improper integral of E[X^n] for the case n=1. Anyhow, I wanted to generalize this without success. I stumbled upon this thread here: https://www.physicsforums.com/threads/how-to-prove-the-cauchy-distribution-has-no-moments.992416/ I really enjoyed the proof...

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