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ertagon2

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View attachment 7799

is this right ?6(1).

p$\implies$q,

$\lnot$q$\therefore\lnot$p,

Modus tollens

6(2).

p$\implies$q,

q$\implies$r,

q$\therefore$r,

Transitivity

6(3).

p$\implies$q,

q$\therefore$p.

Converse fallacy

7. I have no idea what I'm doing please explain.

is this right ?6(1).

p$\implies$q,

$\lnot$q$\therefore\lnot$p,

Modus tollens

6(2).

p$\implies$q,

q$\implies$r,

q$\therefore$r,

Transitivity

6(3).

p$\implies$q,

q$\therefore$p.

Converse fallacy

7. I have no idea what I'm doing please explain.