Trying to solve 3x3 determinant with two zeros

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    3x3 Determinant
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The discussion centers on solving a 3x3 determinant related to the tensions in three wires supporting a flowerpot in equilibrium. The equations provided for the forces in the x, y, and z directions are scrutinized, revealing discrepancies in the coefficients for Tab, which lead to incorrect tension calculations. Cramer's rule is mentioned as a method for finding the tensions, but it is suggested that the user's equations may be flawed since the results do not align with expected values. The conversation emphasizes that if established mathematical methods like Cramer's rule yield unexpected results, it indicates an error in the original equations rather than a failure of the method itself. Ultimately, the need for accurate coefficients and equations is highlighted to correctly determine the tension in the wires.
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Homework Statement


3 wires and unknown tensions: Tab, Tbc, Tbd
Flowerpot being suspended in equilibrium

Code:
Fx =  .05Tab - 0.728Tbc - 0.728Tbd = 0 lbs
Fy = -.05Tab + 0.485Tbc + 0.485Tbd = 20 lbs (weight of flower pot)
Fz =    0Tab + 0.485Tbc - 0.485Tbd = 0 lbs


Homework Equations



Is it possible to find tension in one of these wires?

The Attempt at a Solution



Using Cramers rule, came up with

Code:
-14.1232/0.117855

which was incorrect.
 
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You seem to have made an arithmetic error somewhere. Your answer for Tab is off by a factor of 10.
 
I went over it again today and got the same answer :(
back of the book lists 17 lbs for Tab. Here is the determinant I used,

2n0q0i9.png


resulting in

\frac{-7.0616-7.0616}{(-0.1176125)+(0.17654)-(-0.017654)-(0.1176125)}

= 119.83 lbs, Tab
 
Are the coefficients of Tab equal to 0.5 (third post) or 0.05 (original post)? That's the factor of 10 difference between our answers. So the good news is you're basically calculating Tab correctly using Cramer's rule. The bad news is, if Tab is supposed to be 17 lb, your equations are wrong.
 
0.5, sorry. Not sure where the equations may have gone wrong.
 
Just a guess, but I'd expect the coefficients of Tab should be either \pm 1/\sqrt{2} or one of them should be \pm \sqrt{3}/{2}.

More generally, if you form a vector from the coefficients of Tab, the norm of the vector should be 1.
 
Last edited:
I went over the numbers with someone else in my class who also verifies that the coordinates used are correct. It sounds like this problem can be solved using a graphing calculator, but its strange that I was unable to solve it using cramers rule.
 
It's not strange that Cramer's rule doesn't work. What's strange is you concluding Cramer's rule only works some of the time rather than concluding your equations are wrong or that you are making some other mistake. If a proved result, like Cramer's rule, doesn't seem to be working, that's an indication that there's something else is wrong.

I can tell you that if you and your classmate got exactly the same equations, you and your classmate are wrong. If your classmate claims to have gotten the right answer from those equations, he or she is making yet another mistake.

I can read off the components of Tab from your equations. According to them, the force Tab is equal to\vec{T}_{ab} = \frac{T_{ab}}{2} \mathbf{\hat{i}} + \frac{T_{ab}}{2} \mathbf{\hat{j}}where Tab=|Tab|. But this implies that<br /> \lvert \vec{T}_{ab} \rvert = T_{ab} \sqrt{\left(\frac{1}{2}\right)^2+\left(\frac{1}{2}\right)^2} = T_{ab}\frac{\sqrt{2}}{2} \ne T_{ab}which is a contradiction, which in turn indicates your equations are wrong.
 
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