Trying to work out the speed of a relativistic electron

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SUMMARY

The discussion focuses on calculating the speed of a relativistic electron with an energy of 1010 eV. It is established that this energy represents the total energy, significantly exceeding the rest energy. The correct approach to find the speed involves using the equation β = pc/E, and applying a binomial expansion for p due to the relationship between rest mass and total energy. The final expression for speed is derived as v/c = √(1 - (E02/E2)), indicating that the speed approaches the speed of light.

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Elfrae
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Homework Statement



I have a relativistic electron with energy 10^10 eV and I want to work out its speed. I'm not told if that's total energy or just kinetic energy - which is the sensible assumption to make?


Homework Equations



(E_tot)^2 = p^2*c^2 + m0^2*c^4

p = gamma*mv

gamma = sqrt(1/1-beta^2)

beta = v/c

The Attempt at a Solution



I tried rearranging the above equations to get an expression for v, but I keep getting stupid answers (v = c, v > c).

I have converted the energy into J and assumed that it is the total energy. Can anyone tell me what I'm doing wrong?

Thanks!
 
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That's the total energy, which is much greater than the rest energy, so your answer should come out very close to c. I suggest you calculate the velocity using β=pc/E. You also might want to use a binomial expansion to approximate p since m0<<E.
 
I think that it is better to try this (not to use p, almost the same as vela wrote)
[tex]E = {\gamma}mc^2 = \frac{mc^2}{\sqrt{1-v^2/c^2}}[/tex]
[tex]\frac{v^2}{c^2}=1- \frac{{E_0}^2}{E^2}[/tex]
[tex]\frac{v}{c}=\sqrt{1- \frac{{E_0}^2}{E^2}} \approx 1-\frac{1}{2} \frac{{E_0}^2}{E^2}[/tex]
 
Last edited:

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