Tug of War: Explaining Two True Statements

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SUMMARY

The discussion centers on the physics of a tug of war, specifically addressing two true statements: that both teams must pull equally hard and that the team pushing harder against the ground wins. The tension in the rope, denoted as T, is the force exerted by the rope on each team, which remains constant regardless of individual pulling forces. The second statement is explained through the concept of friction, where increased normal force from pushing harder against the ground results in greater friction, preventing slipping and enhancing stability during the competition.

PREREQUISITES
  • Understanding of Newton's Third Law of Motion
  • Basic knowledge of friction and normal force
  • Familiarity with tension in ropes and forces in equilibrium
  • Concept of static and kinetic friction coefficients
NEXT STEPS
  • Study Newton's Third Law of Motion in detail
  • Explore the concept of friction, including static and kinetic friction coefficients
  • Learn about forces in equilibrium and their applications in real-world scenarios
  • Investigate the role of tension in various physical systems
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Students of physics, educators explaining mechanics, and anyone interested in understanding the dynamics of forces in competitive scenarios like tug of war.

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Homework Statement



Both the following statements are true; explain them. Two teams having a tug of war
must always pull equally hard on one another. The team that pushes harder against the
ground wins.


Homework Equations



Friction = uN

The Attempt at a Solution



For the first statement...During a tug of war the teams must pull equally hard, or else one of them would have won, right?

As for the second statement : By pushing harder against the ground, the normal force experienced, hence friction, would be larger, so the competitors slip less easily, then?

(I kinda get the concept in mind...but how to explain it in words??)

Thanks in advance!
 
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annatar said:
For the first statement...During a tug of war the teams must pull equally hard, or else one of them would have won, right?

Nope, even if one team pulls harder than the other, the force they exert on each other will be the same. Think about the tension in the rope. If the tension in the rope is T, what force does the rope exert on each team?
 
dx said:
Nope, even if one team pulls harder than the other, the force they exert on each other will be the same. Think about the tension in the rope. If the tension in the rope is T, what force does the rope exert on each team?

Isn't it the tension T then?

BTW, does T equals: (your own pulling force's reaction + opponent's pulling force)?
 

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