Finding Force of Friction - Tug of War Problem

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SUMMARY

The force of friction between Bill's feet and the ground in the tug of war problem is 200 N. Since Joe exerts a pulling force of 200 N and Bill moves at a constant velocity, the net force acting on Bill is zero, indicating that the kinetic frictional force must equal the pulling force. This conclusion is derived from Newton's second law and is confirmed by analyzing the free body diagram of the scenario.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of kinetic friction and its formula, μkF
  • Ability to interpret free body diagrams
  • Basic grasp of forces and motion concepts
NEXT STEPS
  • Study the principles of Newton's second law in detail
  • Learn about the coefficients of kinetic friction and their applications
  • Practice drawing and analyzing free body diagrams in various scenarios
  • Explore real-world applications of friction in sports and mechanics
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for practical examples of friction in action.

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Homework Statement


Joe and Bill are playing tug of war. Joe is pulling with a force of 200 N. Bill is simply hanging on, but skidding toward Joe at a constant velocity. What is the force of friction between Bill's feet and the ground?

A) Greater than 200N but less than 400N
B) Less than 200N
C) 400N
D) 200N

Homework Equations


[Kinetic Frictional Force] = μkF


The Attempt at a Solution


Since Joe is pulling with a force of 200N and there is no acceleration (constant velocity), the net force is zero. The kinetic frictional force should be equal to 200N.
 
Physics news on Phys.org
Yep, you got it. Whenever you're presented with one of these problems involving Newton's second law, the best thing to do is to draw a free body diagram and think of the net force on the object. It looks like that's how you went at this problem, so keep it up!
 

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