Turbulent drag force equation for area, speed and density

[Try hard]

Can anyone give me a relationship for the turbulent drag force on an object with a cross sectional area A and a speed v in a medium with density p please?
Thanks

 

[kenhcm]

Maybe this is the one you need, http://hyperphysics.phy-astr.gsu.edu/hbase/airfri.html


Kenneth

 

[wais]

for your question! The relationship for the turbulent drag force on an object with a cross sectional area A and a speed v in a medium with density p can be expressed as:

F = 0.5 * p * v^2 * CD * A

where F is the drag force, p is the density of the medium, v is the speed of the object, and CD is the drag coefficient. The drag coefficient takes into account the shape and surface properties of the object, and can vary depending on the Reynolds number, which is a dimensionless parameter used to characterize the type of flow (laminar or turbulent).

In turbulent flow, the drag coefficient is typically higher than in laminar flow, resulting in a higher drag force on the object. This is because in turbulent flow, there is more mixing and exchange of momentum between the object and the surrounding fluid, leading to a higher resistance force.

It is worth noting that this relationship is based on the assumption of steady, incompressible flow. In real-world situations, there may be other factors that can affect the drag force, such as the presence of obstacles or changes in the flow direction. Additionally, this relationship may not hold at very high speeds or in highly viscous fluids.

I hope this helps answer your question. Keep in mind that this is a simplified explanation and there may be other factors at play in specific situations. If you need more information, I recommend consulting a fluid dynamics textbook or speaking with a expert in the field. Best of luck!