Two cars with constant acceleration meeting

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SUMMARY

The problem involves two cars accelerating towards each other on a 21.0m road, with the left car accelerating at 2.4m/s² and the right car at 1.8m/s². The left car travels 9 meters before meeting the right car, which travels 12 meters. The initial calculations incorrectly attributed the distances to the wrong cars, leading to confusion. The correct approach confirms that the left car indeed covers 9 meters before the two cars meet.

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  • Understanding of kinematic equations for uniformly accelerated motion
  • Basic algebra for solving quadratic equations
  • Knowledge of relative motion concepts
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  • Practice solving problems involving multiple objects in motion
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Homework Statement


Two cars travel towards one another on a 21.0m road, the car traveling to the left has an acceleration a_L=2.4m/s^2 the other car an a_R=1.8m/s^2. What is the distance traveled by the left car up to the meeting point?

Homework Equations


Left Car Right Car
O------------------|--------------------------------O
------->1.8m/s^2 2.4m/s^2<-------

The Attempt at a Solution


0.9t^2=21-1.2t^2
2.1t^2=21
t^2=10
t=sqrt(10)
0.9(10)=9m
So the left car should have traveled 9 meters and the right 12m, but it's not right and I don't see why.
 
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Looks like you've calculated the distance for the car moving right rather than the car moving left.
 

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