Two definitions of locally compact

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SUMMARY

The discussion centers on the proof of proposition A.6.2.(1), which establishes the equivalence of two definitions of "locally compact" in Hausdorff spaces. The user initially struggled with understanding why the set F is a subset of U_1. After analysis, they concluded that since V_2 is open in the topology of K_x, there exists an open set V_2' such that V_2 equals K_x intersected with V_2'. This leads to the conclusion that K_x minus V_2' is indeed a subset of U_1, confirming the relationship between these sets.

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Fredrik
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I'm trying to understand the proof of (ii)\Rightarrow(i) of proposition A.6.2.(1) here. The theorem says that the given definition of "locally compact" is equivalent to a simpler one when the space is Hausdorff. I found the proof quite hard to follow. After a few hours of frustration I'm down to one last detail. Why is F\subset U_1? It seems to me that F could contain limit points of U_1 that aren't in U_1.

Edit: I figured it out. The set V_2 is open in the topology of K_x, so there's an open set V_2' such that V_2=K_x\cap V_2'. This implies that

F=K_x-V_2=K_x-(K_x\cap V_2')=K_x-V_2'.

We also have K_x-U_1\subset V_2\subset V_2', and this implies that

K_x-V_2'\subset K_x-(K_x-U_1)=K_x\cap U_1\subset U_1.
 
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Thanks for posting the answer.
 
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