chart2006
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Homework Statement
The two-dimensional motion of a particle is defined by the relationship [tex]r = \frac {1}{sin\theta - cos\theta}[/tex] and [tex]tan\theta = 1 + \frac {1}{t^2}[/tex], where [tex]r[/tex] and [tex]\theta[/tex] are expressed in meters and radians, respectively, and [tex]t[/tex] is expressed in seconds. Determine (a) the magnitudes of velocity and acceleration at any instant, (b) the radius of curvature of the path.
Homework Equations
[tex]r = \frac {1}{sin\theta - cos\theta}[/tex]
[tex]tan\theta = 1 + \frac {1}{t^2}[/tex]
The Attempt at a Solution
I've made a few attempts but they seem way more complicated than the problem should be I think. I'm assuming I need to solve [tex]tan\theta[/tex] for [tex]\theta[/tex]. Once I've done that I figure I'd need to differentiate both [tex]r[/tex] and [tex]\theta[/tex] to find [tex]\dot{r}, \ddot{r}, \dot{\theta}, \ddot{\theta}[/tex].
I don't know if I'm on the correct route but any help would be appreciated. thanks!