1. The problem statement, all variables and given/known data Block 1, of mass m1 = 0.700kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2. Assume that the blocks accelerate downword with an acceleration of magnitude = 0.250m/s^2 and that the coefficient of kinetic friction between block 2 and the plane is u = 0.200. Tried to attach a good picture of the angle at which the block is 30 2. Relevant equations m2a=T-f-m2gsin(30) With T=6.69 F=un Which n=8.5 so then it would be 1.7 3. The attempt at a solution well to set it up im not sure if im right but i tried to sub all know values into the above eq M2(2.50m/s^2)=6.69-1.7-M2(9.8m/s^2)Sin(30) i keep geting wrong answer + i dont konw how to solve when M2 is on both sides? What do i do. I know the answer has to be smaller than .700kg because if it were larger they would not move.