Two Masses, a Pully, and an Inclinde Plane

[Robdog]

Homework Statement

Block 1, of mass m1 = 0.700kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2. Assume that the blocks accelerate downword with an acceleration of magnitude = 0.250m/s^2 and that the coefficient of kinetic friction between block 2 and the plane is u = 0.200.

Tried to attach a good picture of the angle at which the block is 30

Homework Equations

m2a=T-f-m2gsin(30)

With T=6.69
F=un Which n=8.5 so then it would be 1.7

The Attempt at a Solution

well to set it up I am not sure if I am right but i tried to sub all know values into the above eq

M2(2.50m/s^2)=6.69-1.7-M2(9.8m/s^2)Sin(30)

i keep geting wrong answer + i don't konw how to solve when M2 is on both sides? What do i do. I know the answer has to be smaller than .700kg because if it were larger they would not move.

 

[Robdog]

any idea?

 

[Doc Al]

m2a=T-f-m2gsin(30)

Good. That's Newton's 2nd law applied to mass 2. Do the same for mass 1.

With T=6.69

How do you know the tension?