Two Masses, a Pully, and an Inclinde Plane

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SUMMARY

The discussion focuses on a physics problem involving two blocks connected by a massless, frictionless pulley. Block 1 has a mass of 0.700 kg and accelerates downward at 0.250 m/s², while Block 2 experiences kinetic friction with a coefficient of 0.200 on an inclined plane at a 30-degree angle. The tension in the system is calculated to be 6.69 N, and the user struggles with the equation m2a = T - f - m2gsin(30) due to the presence of m2 on both sides of the equation. The user seeks clarification on how to solve for m2 effectively.

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  • Understanding of Newton's Second Law of Motion
  • Familiarity with the concepts of tension and friction
  • Knowledge of basic trigonometry, specifically sine functions
  • Ability to manipulate algebraic equations
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of problem-solving in dynamics involving pulleys and inclined planes.

Robdog
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Homework Statement



Block 1, of mass m1 = 0.700kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2. Assume that the blocks accelerate downword with an acceleration of magnitude = 0.250m/s^2 and that the coefficient of kinetic friction between block 2 and the plane is u = 0.200.

Tried to attach a good picture of the angle at which the block is 30

Homework Equations



m2a=T-f-m2gsin(30)

With T=6.69
F=un Which n=8.5 so then it would be 1.7

The Attempt at a Solution



well to set it up I am not sure if I am right but i tried to sub all know values into the above eq

M2(2.50m/s^2)=6.69-1.7-M2(9.8m/s^2)Sin(30)

i keep geting wrong answer + i don't konw how to solve when M2 is on both sides? What do i do. I know the answer has to be smaller than .700kg because if it were larger they would not move.
 

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  • MLD_2l_2_v2_2_a.jpg
    MLD_2l_2_v2_2_a.jpg
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any idea?
 
Robdog said:
m2a=T-f-m2gsin(30)
Good. That's Newton's 2nd law applied to mass 2. Do the same for mass 1.

With T=6.69
How do you know the tension?
 

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