- #1

- 971

- 40

## Homework Statement

## Homework Equations

## The Attempt at a Solution

Suppose tension in the left string mAM be T

_{1}and tension in the right string mBM be T

_{2}.When the particles cross each other then the angle made by string mA and mB with vertical is α and that made by AM and BM be β . The speed of m is u and that of M is v .

The work done by tension would be zero , so

-(T

_{1}cosα)u + (T

_{1}cosβ)v - (T

_{2}cosα)u + (T

_{2}cosβ)v = 0

By symmetry I believe the tensions should be equal so if I put T

_{1}= T

_{2}

I get , (cosα)u = (cosβ)v .

But now I do not think α is equal to β when the masses cross each other .

Am I thinking correctly ?

Thanks