Two long parallel wires are a center-to-center distance of 1.10 cm apart and carry equal anti-parallel currents of 9.70 A. Find the magnitude of the magnetic field at the point P which is equidistant from the wires. (R = 10.00 cm). (See Attachment for orientation)
I = 9.7 A
Distance from current source = √(.12+(.011/2)2) = 10.015 cm
Binfinite wire= μi*I/2*pi*r
The Attempt at a Solution
Knowing the upper wire's magnetic field rotates counterclockwise and the lower wire rotates clockwise using RHR 2. So the y components at point P are equal but opposite. So we know the magnitude at Point P is going to be 2 times the x component of the magnetic field produced by either wire, which is represented as...
where cos(θ) = .1/√(.12+(.011/2)2))
So Btotal = 3.868e-5 T but it is telling me that is wrong.
Thanks for any help, it is greatly appreciated.
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