Two-point source interference pattern

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SUMMARY

The discussion focuses on calculating the angles of nodal lines in a two-point source interference pattern generated by two sources operating in phase at 1.0 Hz, separated by 2.0 m, with a wavelength of 0.60 m. The formula used is sin(θ) = (n - 0.5)(λ/d), where n represents the order of the nodal lines. Participants confirm that substituting values for n (1, 2, 3, etc.) will yield the necessary angles, and suggest using a spreadsheet for efficiency in calculations.

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Homework Statement



A two-point source interference pattern is generated by sources operating in phase at 1.0 Hz. The sources are 2.0 m apart and the wavelength of the waves is 0.60 m. At what angles, measured from the centre line of the pattern, are the nodal lines produced located?



They want to sub in for various values of n? or am i missing something it seems to simple? i am using sintheta=(n-0.5)(\lambda/d)
 
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Welcome to PF!
Yes, sub in n = 1, 2, 3, ... It looks like an infinite amount of work, but you will find that only a few values of n need be worked out. It is a little repetitive - a spreadsheet formula would be quickest!
 
thanks
 

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