Adding a 3rd Source to a 2 Source Interference Pattern

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Homework Help Overview

The discussion revolves around a double slit interference pattern and the implications of adding a third slit between the existing two. The problem involves analyzing how this addition affects the interference at specific points labeled X, Y, and Z, particularly in terms of whether they will be points of maximum, minimum, or neither interference.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the conditions for constructive and destructive interference based on the phase relationships between the slits. There is an examination of how the path length differences affect the interference pattern at points X, Y, and Z.

Discussion Status

Some participants express agreement with the reasoning for points X and Z, while others suggest that a reevaluation of point Y may lead to a different conclusion regarding its interference status. The discussion is ongoing with various interpretations being explored.

Contextual Notes

Participants note the complexity introduced by the third slit and the need to consider phase differences carefully. There is also mention of the limitations of the forum's image handling capabilities, which may affect the clarity of the visual aids used in the discussion.

kosovo dave
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http://imageshack.com/a/img834/5921/7iap.jpg

Homework Statement


Consider the double slit pattern shown above where the distance between slits is d. Each lettered point is labeled according to ΔD, the difference in distances from the slits to that point. ΔD is expressed in terms of wavelength, λ. Suppose that a third slit were inserted between the two slits such that the distance between adjacent slits becomes d/2. Would each point X,Y,Z be a max, min, or neither?

Homework Equations


ΔD=dsinΘ
ΔD=mλ constructive interference
ΔD=λ/n destructive interference, where n= # of slits
ΔD=mλ/n neither constructive nor destructive, where m=0,n,2n,3n,...

The Attempt at a Solution


At first I tried playing around with those equations but I ended up confusing myself. Then I realized that for a fringe to be a principal maximum, all of the light sources must be in phase there. At each point of constructive interference for two sources, S1 and S3 will still be in phase, but each will be out of phase with the new source S2 (halfway between S1 and S3). Similarly, S1 and S3 will interfere destructively at a point of destructive interference for two sources, but both will not be out of phase with S2. So I'm thinking none of the points will be max/min. Is my reasoning/answer correct?

Let me know if my amazing drawing/description are not clear enough and I will try to elaborate.
 
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Also, sorry for the image size. Is there a way to shrink it or would I have to reupload a smaller image?
 
I agree with your reasoning for points X & Z.

For point Y, the path lengths from S1 and S3 differ by __×λ. Therefore, each of those path lengths differs from the S2 path length by ___×λ.

If you fill in the blanks above, I think you will arrive at a different conclusion for point Y.

Hope that helps!

p.s. I have replaced the image in your original post with a link to it. Unfortunately, our forum software does not provide for resizing of images. You can upload a resized -- and cropped -- drawing if you wish. If you do, I could then edit your 1st post to include the reduced drawing. (A 640-pixels-or-less image width would definitely fit okay here.)
 
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It took me awhile to see what you were saying, but Y should have constructive interference right? Since S1 and S3 are separated by 2 wavelengths, S2 is out of phase by one wavelength with each.
 
Yes, correct. :smile:
 

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