A block is sent sliding down a ramp. Its speeds at points A and B are 1.85 m/s and 2.60 m/s, respectively. Next, it is again sent sliding down the ramp, but this time its speed at point A is 3.95 m/s. What then is its speed at point B?
(point a is logically higher on the ramp than point b)
The goal of this one is to use conservation of mechanical energy to deduce the final velocity of the second trial. Heres what i have:
since this is clearly a problem that does not need to involve the mass in the mechanical energy equation, i set something up that should describe the motion and the change in kinetic energy of this object:
gh(initial) + (v(initial)^2)/2 = gh(final) + (v(final)^2)/2
This should be set up twice (once for each set of velocities, the second set containing an unknown velocity for vfinal.)
What i'm confused about is how the kinetic energy and work equations come into play if at all. There is clearly no frictional force acting on the block so the acceleration is constant. Where do i go from here? Anybody have a suggestion on how to tackle the heights or weather or not it is necessary to find those quantities? i assume it is but i could very well be wrong.