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Typing operators in PF threads

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  1. Jun 23, 2015 #1
    Hi, I am new here. I don't know how can I type mathematical operators or symbols here. Can anyone help me out?
     
  2. jcsd
  3. Jun 23, 2015 #2

    RUber

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    Homework Helper

  4. Jun 23, 2015 #3
    Lots of codes there, but still a solution. Thank you
     
  5. Jun 23, 2015 #4

    dlgoff

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    Science Advisor
    Gold Member

    If you just need something quick when replying to a post, click on the redactor_s.png and you'll get a list of symbols that you can pick from that will be inserted.
     
  6. Jun 23, 2015 #5
    Yeah, it's working. Thanks
     
  7. Jun 24, 2015 #6

    Mark44

    Staff: Mentor

    The LaTeX I use most often is for fractions, integrals, limits, and sums.
    For inline LaTeX, use two # symbols at the beginning and two more at the end of the LaTeX script.
    For standalone LaTeX, use two $ symbols at the beginning and two more at the end. I don't care much for the standalone forms, because our new forum software centers the stuff on the middle of the line.

    Here is some sample script without the # symbols fore and aft, so you can see what it looks like, followed by how the script renders in both inline and standalone form:

    Fractions:
    \frac {a + b}{c + d}
    Renders as:
    ##\frac {a + b}{c + d}##
    $$\frac {a + b}{c + d}$$

    Integrals:
    \int_{x = 0}^{12} f(t) dt
    ##\int_{x = 0}^{12} f(t) dt##
    $$\int_{x = 0}^{12} f(t) dt$$

    Limits:
    \lim_{n \to \infty} \frac{n}{2n - 1} = \frac{1}{2}
    Renders as:
    ##\lim_{n \to \infty} \frac{n}{2n - 1} = \frac{1}{2}##
    $$\lim_{n \to \infty} \frac{n}{2n - 1} = \frac{1}{2}$$

    Sums:
    \sum_{n = 0}^{N}a_n
    ##\sum_{n = 0}^{N}a_n##
    $$\sum_{n = 0}^{N}a_n$$
     
  8. Jun 24, 2015 #7
    Wow! I actually was looking forlimits. But what is inline and standalone latex?
     
  9. Jun 24, 2015 #8

    Mark44

    Staff: Mentor

    Inline is for inserting the expression right in the middle of surrounding text, such a ##\sqrt{2x + 1}##.

    Standalone puts a slightly more expanded version on its own line: $$\sqrt{2x + 1}$$

    BTW, what I typed was \sqrt{2x + 1}

    For a cube root, \sqrt[3]{2x + 1}
     
  10. Jun 24, 2015 #9
    Making an attempt:

    ## \frac {a + b} {c + d} ##

    ## y = a x^2 + b x + c ##

    ## \Delta \theta = \omega_0 t + \frac {1}{2} \alpha t^2 ##
     
  11. Jun 24, 2015 #10
    \frac{1}{2} nothing happens!
     
  12. Jun 24, 2015 #11
    Put that text between double hash tags.

    ## \frac{1}{2} ##
     
  13. Jun 24, 2015 #12
    ##\frac{1}{2}##

    Great!
     
  14. Jun 24, 2015 #13

    Mark44

    Staff: Mentor

    Like I said earlier,
     
  15. Jun 24, 2015 #14
    Yeah, now it's all clear to me. Thanks
     
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