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U ^ 5/2 /5/2 - u^ 1/2/3/2 +c intergration

  1. Oct 10, 2008 #1
    [tex]\int\sqrt{1+x} dx =[/tex]

    [tex]\int (u-1)\sqrt{u} du[/tex]


    were does the 3/2 and the 1/2 come from in

    u ^ 5/2 /5/2 - u^ 1/2/3/2 +c
     
  2. jcsd
  3. Oct 10, 2008 #2
    Re: intergration

    They come from the exponents of u.
    [tex](u-1)\sqrt{u} = u\sqrt{u}-\sqrt{u} = u^{3/2} - y^{1/2}[/tex]
     
  4. Oct 10, 2008 #3
    Re: intergration

    so

    u\sqrt{u} = 3/2 ok i remember some thing from my previouse course saying that thank you again for your help.
     
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