U ^ 5/2 /5/2 - u^ 1/2/3/2 +c intergration

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The discussion centers on the integration of the function \(\int\sqrt{1+x} dx\) and its transformation into \(\int (u-1)\sqrt{u} du\). The exponents \(3/2\) and \(1/2\) arise from the manipulation of the expression \(u\sqrt{u} = u^{3/2} - u^{1/2}\). Participants clarify that these exponents are derived directly from the properties of exponents in the context of integration. The conversation emphasizes the importance of understanding exponent rules in calculus.

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[tex]\int\sqrt{1+x} dx =[/tex]

[tex]\int (u-1)\sqrt{u} du[/tex]


were does the 3/2 and the 1/2 come from in

u ^ 5/2 /5/2 - u^ 1/2/3/2 +c
 
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They come from the exponents of u.
[tex](u-1)\sqrt{u} = u\sqrt{u}-\sqrt{u} = u^{3/2} - y^{1/2}[/tex]
 


so

u\sqrt{u} = 3/2 ok i remember some thing from my previouse course saying that thank you again for your help.
 

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