U ^ 5/2 /5/2 - u^ 1/2/3/2 +c intergration

[morbello]

$$\int\sqrt{1+x} dx =$$

$$\int (u-1)\sqrt{u} du$$


were does the 3/2 and the 1/2 come from in

u ^ 5/2 /5/2 - u^ 1/2/3/2 +c

 

[gunch]

They come from the exponents of u.
$$(u-1)\sqrt{u} = u\sqrt{u}-\sqrt{u} = u^{3/2} - y^{1/2}$$

 

[morbello]

so

u\sqrt{u} = 3/2 ok i remember some thing from my previouse course saying that thank you again for your help.