Unbanked and banked Curves problem

  • Thread starter dvela
  • Start date
  • #1
4
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1. A roller coaster of mass 320 kg (including passengers) travels around a horizontal curve of radius 35 m. Its speed is 16 m/s. What is the magnitude and direction of the total force exerted on the car by the track?



Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
53
0
thats the entire problem?
 
  • #3
4
0
yeah
 
  • #4
53
0
as always this deals with centripetal acceleration covered by the formula Fc = (mv/r^2)

plug in the values and you get Fc= (320*16*16)/(35)

which solves for 2340.6N

Have a great day.. at least show some effort.
 
Last edited:
  • #5
4
0
i tried that but the answer is supposed to be 3900 N at 53 degrees above the horizontal, but thanks anyways
 
  • #6
53
0
if theres a bank you didn't give me the full question. I cannot see an angle anywhere in the eq'n.. maybe some is cut off or elsewhere on the page..
 
  • #7
99
1
Two forces acting on the roller coaster. Normal force , weight, frictional force.
 
Last edited:
  • #8
tiny-tim
Science Advisor
Homework Helper
25,836
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Welcome to PF!

Hi dvela! Welcome to PF! :wink:

joshmdmd's formula for centripetal acceleration is wrong, it should be v2/r (not v/r2).

Try again. :smile:

(and joshmdmd, please don't give full answers on this forum)

as always this deals with centripetal acceleration covered by the formula Fc = (mv/r^2)

plug in the values and you get Fc= (320*16*16)/(35)

which solves for 2340.6N

Have a great day.. at least show some effort.
 
  • #9
53
0
Two forces acting on the roller coaster. Normal force , weight, frictional force.

There is no Friction in the question and there is normal force, gravitational force and centripetal force. Basically you are looking for magnitude and direction for normal force.. (got an infraction for solving the eq'n completely so i guess im not giving out more xD)
 
  • #10
53
0


Hi dvela! Welcome to PF! :wink:

joshmdmd's formula for centripetal acceleration is wrong, it should be mv2/r (not mv/r2).

Try again. :smile:

(and joshmdmd, please don't give full answers on this forum)

I already edited that out xD
 
  • #11
berkeman
Mentor
60,829
11,215
There is no Friction in the question and there is normal force, gravitational force and centripetal force. Basically you are looking for magnitude and direction for normal force.. (got an infraction for solving the eq'n completely so i guess im not giving out more xD)

They were warnings, not infractions. And as explained, it's fine to give hints and ask probing questions, but it's not okay to solve homework problems for students here.
 

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