- #1

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Thanks!

- Thread starter Ja4Coltrane
- Start date

- #1

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Thanks!

- #2

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The function f:[0,1]->R given by

f(x) = n if x=1/n for some positive integer n

f(x) = 0 else

f(x) = n if x=1/n for some positive integer n

f(x) = 0 else

- #3

- 225

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muchas gracias

- #4

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Okay how about one which isn't Riemann (improper) integrable

- #5

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[tex]\displaystyle\sum_{ k = 1 }^\infty k \chi_{ [ 0, \frac{ 1 }{ k^2 } ] }[/tex]

- #6

matt grime

Science Advisor

Homework Helper

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Um, surely f(x)=1/x for x>0 and f(0)=0 is far simpler, and does everything needed.

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