Uncertain of 2 problems (answers given, but don't know solution-help)

  • Thread starter Thread starter andreguerra
  • Start date Start date
Click For Summary
SUMMARY

This discussion addresses two physics problems involving electrical heating and electrostatics. The first problem calculates the temperature of an electric iron drawing 9 amperes from a 120-volt line, resulting in a final temperature of 231 degrees Celsius after 2 minutes, accounting for 40% heat loss. The second problem determines the radius of a water drop with a net charge of 200 electrons suspended in an electric field of 300 volts/meter, yielding a radius of 6.16 x 10^-7 meters, where the electric force balances the weight of the drop.

PREREQUISITES
  • Understanding of Ohm's Law and electrical power calculations
  • Knowledge of heat transfer principles, specifically thermal energy and heat loss
  • Familiarity with electrostatics, including electric fields and forces
  • Basic concepts of mass and weight in physics
NEXT STEPS
  • Study electrical power calculations using the formula P = VI for various circuits
  • Explore heat transfer mechanisms, focusing on conduction, convection, and radiation
  • Learn about electrostatic forces and their applications in real-world scenarios
  • Investigate the relationship between charge, mass, and electric fields in fluid dynamics
USEFUL FOR

Students in physics, educators teaching electrical engineering concepts, and professionals working in fields related to thermodynamics and electrostatics.

andreguerra
Messages
1
Reaction score
0
Uncertain of 2 problems (answers given, but don't know solution--help!)

1. An electric iron draws 9 amperes from a 120-volt line. The iron's mass is 0.8 kilograms, and it is originally at 20 degrees Celsius. 40% of the heat is lost to the room by radiation. What will the temperature of the iron be 2.0 minutes after it's connected. Assume constant resistance.
Answer is 231 degrees Celsius (note that 60% of power input goes to heating the iron)

2. A drop of water in a fog has a net charge of 200 electrons. What is the radius of the drop if it is suspended motionless on a day when the Earth's electric field is 300 volts/meter?
Answer is radius = 6.16 x 10^-7 meters; hint: electric force must balance weight of drop

Thank you very much!
 
Physics news on Phys.org
Hint for 1: Calculate the electrical energy consumed by the iron in 2 minutes.
Hint for 2: Find the mass of the water drop.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
11K
Replies
2
Views
13K
Replies
3
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K