Uncertainty momentum position velocity

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SUMMARY

The discussion focuses on calculating the minimum uncertainty in the position of an electron using the Heisenberg uncertainty principle. The relevant equation is delta(x) * delta(P) ≥ hbar/2, where delta(P) is defined as delta(v) multiplied by the mass of the electron. The user confirms that the specific values for position and velocity are not necessary for this calculation, as the uncertainty can be derived directly from the given uncertainty in velocity (B) and the mass of the electron.

PREREQUISITES
  • Understanding of the Heisenberg uncertainty principle
  • Knowledge of quantum mechanics terminology
  • Familiarity with the concept of hbar (reduced Planck's constant)
  • Basic principles of momentum in physics
NEXT STEPS
  • Study the implications of the Heisenberg uncertainty principle in quantum mechanics
  • Learn about the calculation of uncertainties in quantum systems
  • Explore the relationship between position and momentum in wave-particle duality
  • Investigate the role of mass in determining momentum uncertainty
USEFUL FOR

Students of quantum mechanics, physicists, and anyone interested in the principles of uncertainty in particle physics.

jackxxny
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Homework Statement



I have a dilemma. My problem states that an electron that is in position 2.34 nm along the x axis, travels along the x-axis with a certain speed (A) and a with the uncertainty in the velocity (B). I am asked to calculate the minimum uncertainty in the position.

Homework Equations



I know

delta(x)*delta(P)>= hbar/2
delta(P)= delta(v)*(mass electron)

for delta(v) I'm going to use the B

The Attempt at a Solution



I have done this

delta (x) = (hbar)/2*(delta(v))*(mass electron)

my question is, i don't need the position and the velocity then
 
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jackxxny said:
I have done this

delta (x) = (hbar)/2*(delta(v))*(mass electron)
Careful with parentheses--it's hard to tell if you are multiplying or dividing by delta(P).

my question is, i don't need the position and the velocity then
That's right--you don't need that information.
 

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