Uncertainty momentum position velocity

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jackxxny
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Homework Statement



I have a dilemma. My problem states that an electron that is in position 2.34 nm along the x axis, travels along the x-axis with a certain speed (A) and a with the uncertainty in the velocity (B). I am asked to calculate the minimum uncertainty in the position.

Homework Equations



I know

delta(x)*delta(P)>= hbar/2
delta(P)= delta(v)*(mass electron)

for delta(v) I'm going to use the B

The Attempt at a Solution



I have done this

delta (x) = (hbar)/2*(delta(v))*(mass electron)

my question is, i don't need the position and the velocity then
 
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jackxxny said:
I have done this

delta (x) = (hbar)/2*(delta(v))*(mass electron)
Careful with parentheses--it's hard to tell if you are multiplying or dividing by delta(P).

my question is, i don't need the position and the velocity then
That's right--you don't need that information.