1. The problem statement, all variables and given/known data A mass of 10 kg is hanging from a spring with k=2500N/m that is attached to a roof (see pic). The length of the spring when it is not in tension is l0=0.5 m. At the time t=0, the mass has a speed of v0=0.5 m/s when it passes the system's equilibrium position. Determine a) The equilibrium position b) The natural frequency, fn c) The period, T d) The position of the mass as a function of time, t, measured from the roof - draw an approximate graph. 2. Relevant equations F=ma Undamped motion Wn^2 = k/m fn=Wn/2pi T=1/fn x''+(Wn^2)x=C x(t)=Acos(Wn t) + Bsin(Wn t) + c/(Wn^2) 3. The attempt at a solution I think I did this correctly. In part b I'm not really sure how to deal with the fact that the formula seems to be giving me Wn^2 = - k/m , but I just took the absolute value. I have no idea why the images keep being uploaded sideways. Incredibly annoying but I can't seem to fix it.