# Underground Storage Tank subjected to any loading when it is in burying? (1 Viewer)

### Users Who Are Viewing This Thread (Users: 0, Guests: 1)

#### baleno911

:rofl: As i know there was the load for the weight of tank itself, second will be the volume of the soil on the top of the tank.
Since the horizontal tank is round at the upper part, so is that the force wil be uniformlly distributed along the curve surface?
Is that any force of stress applied from the side? bottom part?

Could i get info in more details in any website?

i appreciate it! :!!)

#### moo

If I'm not mistaken, the support is from both the top and bottom curves of the cylinder when positioned on it's side (with a bit of support also from the vertical end walls).

In this case the cylinder is basically two "arches" joined together. One arch is right side up and the other is upside down.

moo
__________________
moo (moo') adj. Of no practical importance; irrelevant, such as a moo point (i.e. a cow's opinion).

#### civil_dude

Sounds like you might be able to model it just like a big burried pipe. Check out some pipe mfg. sites.

Homework Helper
baleno911 said:
Is that any force of stress applied from the side? bottom part?
Basically, the stress equals $$\sigma = \gamma \cdot z$$, where $$\gamma$$ is the unit weight of the soil, in [kN / m^3], and z the depth. If there is underground water, you'll have to add the hydrostatic pressure, i.e. the pore pressure.

You may want to investigate this link: http://fbe.uwe.ac.uk/public/geocal/SoilMech/stresses/default.htm". (Click on 'stress profile applet'.)

Last edited by a moderator:

### The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving