Underground Storage Tank subjected to any loading when it is in burying?

  • Thread starter baleno911
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  • #1
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Main Question or Discussion Point

:rofl: As i know there was the load for the weight of tank itself, second will be the volume of the soil on the top of the tank.
Since the horizontal tank is round at the upper part, so is that the force wil be uniformlly distributed along the curve surface?
Is that any force of stress applied from the side? bottom part?

Could i get info in more details in any website?

i appreciate it! :!!)
 

Answers and Replies

  • #2
moo
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If I'm not mistaken, the support is from both the top and bottom curves of the cylinder when positioned on it's side (with a bit of support also from the vertical end walls).

In this case the cylinder is basically two "arches" joined together. One arch is right side up and the other is upside down. :wink:

moo
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  • #3
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Sounds like you might be able to model it just like a big burried pipe. Check out some pipe mfg. sites.
 
  • #4
radou
Homework Helper
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baleno911 said:
Is that any force of stress applied from the side? bottom part?
Basically, the stress equals [tex]\sigma = \gamma \cdot z[/tex], where [tex]\gamma[/tex] is the unit weight of the soil, in [kN / m^3], and z the depth. If there is underground water, you'll have to add the hydrostatic pressure, i.e. the pore pressure.

You may want to investigate this link: http://fbe.uwe.ac.uk/public/geocal/SoilMech/stresses/default.htm". (Click on 'stress profile applet'.)
 
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