Understand Affine Subsets & Mappings: Research Project for Undergrads

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Discussion Overview

This discussion revolves around understanding affine subsets and mappings within the context of a research project for undergraduates. The participants explore definitions, properties, and proofs related to affine subsets of vector spaces, including their applications in constructing fractal sets. The conversation is structured around specific topics, with participants seeking clarification and assistance on various aspects of the subject matter.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • Participants discuss the definition of an affine subset and provide an example to illustrate the concept.
  • One participant attempts to prove that the sum of an affine subset and a vector is also affine, presenting a proof structure and seeking feedback.
  • There is a focus on proving that if the zero vector is in an affine subset, then it is a subspace, with participants discussing the necessary axioms.
  • Participants engage in proving specific properties of affine subsets, including closure under addition and scalar multiplication.
  • Some participants express uncertainty about the sufficiency of their proofs and seek clarification on specific steps or definitions.
  • There are exchanges about using specific values for parameters in proofs, such as setting λ = 1/2, and discussions about the implications of these choices.
  • Several participants express a need for additional resources or assistance related to their assignments, indicating a shared struggle with the material.

Areas of Agreement / Disagreement

The discussion reflects a mix of agreement on the definitions and properties of affine subsets, but there is no consensus on the sufficiency of certain proofs or the best approaches to take. Participants express varying levels of confidence in their understanding and the correctness of their reasoning.

Contextual Notes

Participants reference specific mathematical properties and axioms related to affine subsets and vector spaces, but there are unresolved questions regarding the completeness of their proofs and the application of definitions. Some discussions indicate a reliance on assumptions that may not be fully articulated.

Who May Find This Useful

This thread may be useful for undergraduate students studying linear algebra, particularly those focusing on affine geometry, vector spaces, and related mathematical proofs. It may also benefit individuals seeking collaborative support in understanding complex mathematical concepts.

tamintl
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This research project is to help me (I'm an undergraduate) get my head around this topic. It is concerned with affine subsets of a vector space and the mappings between them. As an
application, the construction of certain fractal sets in the plane is considered. It would be considered pretty basic to a seasoned maths student.

I am wanting to learn this so I will be sticking around. I will not just leave. I want to commit to this. Thanks

There are two parts: A and B

If someone is willing to help, I will post each topic AFTER I have fully understood the previous topic. This way it will run in a logical order.

PART A:

----------------------------------------------------------------------------------
Throughout Part A, V will be a real vector space and, for a non-empty subset S of V and
a ε V , the set {x+a: x ε S} will be denoted by S + a

----------------------------------------------------------------------------------

TOPIC 1: Definition of Affine Subset:

An affine subset of V is a non-empty subset M of V with the property that λx+(1-λ)y ε M whenever x,y ε M and λ ε ℝ

To illustrate this concept, show that:

M = { x = (x1,...x4) ε ℝ4 : 2x1-x2+x3 = 1 and x1+4x3-2x4 = 3}

is an affine subset of ℝ4.

I'm not so sure where to start. Opinions welcome

Regards
Tam
 
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Take x and y in M. You must show that \lambda x+ (1-\lambda) y\in M. Call this number z for convenience.

To show that z is in M, you need to show that

2z_1-z_2+z_3=1~\text{and}~z_1+4z_2-2z_4=3

You know that z_i=\lambda x_i + (1-\lambda) y_i so substitute that in.
 


micromass said:
Take x and y in M. You must show that \lambda x+ (1-\lambda) y\in M. Call this number z for convenience.

To show that z is in M, you need to show that

2z_1-z_2+z_3=1~\text{and}~z_1+4z_2-2z_4=3

You know that z_i=\lambda x_i + (1-\lambda) y_i so substitute that in.

Okay great.

So subbing in z we get:

LHS:

2(λx1+(1-λ)y1) - (λx2+(1-λ)y2) + (λx3+(1-λ)y3)

Now taking:

λ(2x1-x2+x3) We know that the bold part = 1

(1-λ)(2y1-y2+y3) We again know that the bold part = 1

so we have λ + (1-λ) = 1 = RHS

AND NOW DO THE SAME WITH THE SECOND PART X1+4X3-2X4 = 3... IVE DONE THAT IN MY OWN TIME.
-------------------------------------------------------------------------------------------------------

So I think I've grasped that. I will look at the next topic and report back when I've had a go. Thanks Micro
 


Now Topic A2

Let M be an affine subset of V.

QUESTION: Prove that M+a is affine for every a ε V and that, if 0 ε M, then M is a subspace

So my attempt:

Proof: x,y is in M+a

take: x = m1+a and y = m2+a for some m1,m2M

Therefore, λ(m1+a) + (1-λ)(m2+a)

Now rearranging gives:

(i) λm1 + (1-λ)m2 which must be in M by definition.

(ii) λa + (1-λ)a
=a(λ+1-λ)
=a

Hence, λm1 + (1-λ)m2 + a is in M+a. So M+a is affine.


I'm unsure of what to do with the zero part of the question?
 


So assume that 0 is in M. You must prove that it is a subspace. So you must check the axioms of being a subspace.
 


micromass said:
So assume that 0 is in M. You must prove that it is a subspace. So you must check the axioms of being a subspace.

OKay, using the definition: Let M be a subspace of vecotr space V. Then M is a subspace of V IFF

i) 0 ε M
ii) x+y ε M for all x,y ε M
iii) λx ε M for all x ε M

(i) holds since we are assuming 0 ε M
(ii) holds since we showed this in the last part of the question
(iii) holds since in the last part of the question λx ε M

Is this enough? I'm unsure of (iii)

Regards
Tam
 


tamintl said:
OKay, using the definition: Let M be a subspace of vecotr space V. Then M is a subspace of V IFF

i) 0 ε M
ii) x+y ε M for all x,y ε M
iii) λx ε M for all x ε M

(i) holds since we are assuming 0 ε M
(ii) holds since we showed this in the last part of the question
(iii) holds since in the last part of the question λx ε M

Is this enough? I'm unsure of (iii)

Regards
Tam

Could you explain (ii) and (iii)?? You have to use the assumption that 0 is in M for all of these questions.
Begin by showing (iii). Apply the definition of M affine on x and 0.
 


micromass said:
Could you explain (ii) and (iii)?? You have to use the assumption that 0 is in M for all of these questions.
Begin by showing (iii). Apply the definition of M affine on x and 0.

Okay, on x,

λx + (1-λ)x will be in M by definition

on 0,

λ(0) + (1-λ)(0) = 0 which is in M since we are assuming 0 ε M

Have I understood you?
 


No. You have to show that for any x and for any λ, that λx is in M.

You know that M is affine, so you know that for any x and for any y, we have that λx+(1-λ)y is in M.
Now choose a special value of y.
 
  • #10
micromass said:
No. You have to show that for any x and for any λ, that λx is in M.

You know that M is affine, so you know that for any x and for any y, we have that λx+(1-λ)y is in M.
Now choose a special value of y.

Oh okay. If we take y=0 (using the condition 0€M)

Then we get (lambda)x + (1-lambda)(0) which is just (lambda)x

So we know for any x and lambda that it will be in M. So that is iii done.

What about ii

Ps: I'm on my phone so sorry for weak notation.

Thanks micro
 
  • #11


For (ii), you need to prove that if x and y are in M, then x+y is in M.

You know that for each r and s in M that

\lambda r+(1-\lambda)s\in M

Now choose the right r and s such that we can conclude that x+y is in M. Use (iii).
 
  • #12
micromass said:
For (ii), you need to prove that if x and y are in M, then x+y is in M.

You know that for each r and s in M that

\lambda r+(1-\lambda)s\in M

Now choose the right r and s such that we can conclude that x+y is in M. Use (iii).

Take r=x and s=0 so since we know (lambda)x is in M, x+0 is in M.

Or could we use the M+a proof?
 
  • #13


bump?
 
  • #14


is it permissible to set λ = 1/2?
 
  • #15


Deveno said:
is it permissible to set λ = 1/2?

Yes, I think...

Edit: taking λ = 1/2

f(x+y) = f(1/2(2x)) + f(1/2(2y))

= 1/2 [ f(2x) + f(2y) ]

taking 2 out gives:

= f(x) + f(y)

Hence closed under addition

Is that sufficient?

Thanks
 
Last edited:
  • #16


tamintl said:
Yes, I think...

Edit: taking λ = 1/2

f(x+y) = f(1/2(2x)) + f(1/2(2y))

= 1/2 [ f(2x) + f(2y) ]

taking 2 out gives:

= f(x) + f(y)

Hence closed under addition

Is that sufficient?

Thanks

where does "f" come from?

my reasoning goes like this: 1/2 and 1/2 sum to 1, so (1/2)x + (1/2)y is an affine combination, that is: (x+y)/2 is in M.

now, use part (iii) to conclude that...
 
  • #17


Deveno said:
where does "f" come from?

my reasoning goes like this: 1/2 and 1/2 sum to 1, so (1/2)x + (1/2)y is an affine combination, that is: (x+y)/2 is in M.

now, use part (iii) to conclude that...

Yeah forget about the 'f's.. yeah that makes sense.

Deveno, if I sent you the question sheet it may be easier for both you and I to understand. Of course, only if you are happy to help. Would that be okay? The reason I ask is that it is hard for me to get my points across since I don't know latex.

Regards
 
  • #18


Hi

I am doing a similar assignment and have been finding it difficult to find relevant material to the questions. However I have found the guidance on this thread very useful so far and was hoping you could send me any further information on this assignment as I think it would be a great help.

Thanks
 
  • #19


I think this is the same assignment as the one I'm doing - I'm basically in the same position as matt90, and have spent hours doing research on this with no luck. I would also really appreciate any additional help you have to offer.
 
  • #20


Thread closed temporarily for Moderation...
 

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