Undergrad Understanding Algebraic Numbers & Proving Them

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SUMMARY

An algebraic number is defined as any number that serves as a solution to a polynomial equation with integer or rational coefficients. Key properties include that all rational numbers are algebraic, deMoivre roots of algebraic numbers are also algebraic, and the sum or product of any two algebraic numbers remains algebraic. The proof of these properties relies on polynomial roots and the finiteness of field extensions, specifically using the relationship between algebraic numbers and their minimal polynomials.

PREREQUISITES
  • Understanding of polynomial equations and roots
  • Familiarity with rational and integer coefficients
  • Knowledge of field extensions in abstract algebra
  • Basic concepts of deMoivre's theorem
NEXT STEPS
  • Study the properties of polynomial roots in algebra
  • Learn about minimal polynomials and their significance in algebraic number theory
  • Explore field extensions and their applications in proving algebraic properties
  • Investigate deMoivre's theorem and its implications for algebraic numbers
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Mathematicians, students of abstract algebra, and anyone interested in the properties and proofs related to algebraic numbers and polynomial equations.

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I'm trying to grok what an algebraic number could look like. Yes, I understand that an algebraic number is any number that could be a solution (root) to a polynomial having integer coefficients (or rational coefficients, since any set of rational coefficients can be made into integers by scaling the entire polynomial equation).

I can't prove it, but it seems that an algebraic number follows a few rules:

- any rational number is an algebraic number

- any deMoivre root of an algebraic number is an algebraic number

- the sum or product of any pair of algebraic numbers is an algebraic number

Is my understanding accurate here? If so, is there any way to prove this?
 
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Yes, these are all true.

- The polynomial ##x-(a/b)## has ##a/b## as a root.

- If ##\alpha## is a root of ##p(x)## and if ##w^n=\alpha##, then ##w## is a root of ##p(x^n).##

- If ##\alpha## and ##\beta## are algebraic, then ##[\mathbb{Q}(\alpha,\beta):\mathbb{Q}]=[\mathbb{Q}(\alpha,\beta):\mathbb{Q}(\alpha)]\cdot [\mathbb{Q}(\alpha):\mathbb{Q}]## is finite, so ##\alpha\beta,\alpha+\beta\in\mathbb{Q}(\alpha,\beta)## are algebraic.

The point in the last argument is that ##[\mathbb{Q}(\gamma):\mathbb{Q}]## is finite if and only if ##\gamma## is algebraic. It's not easy to explicitly describe the minimal polynomial of ##\alpha+\beta## in terms of the minimal polynomials of ##\alpha## and ##\beta.##
 
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