Understanding Beta Particles and Their Role in Radioactivity | Diagram Included

[malawi_glenn]

so for one beta particle there may have infinite number of M points, right?

No!

a Beta particle = an electron; same thing but different name!

Each electron will only have ONE value of energy (M).

you must learn what a beta particle is.

The two points are for same number of paricles... So it means that the probability of measuring two particles, the particles are same, right?

No!

It just means that there is an equal probabilty that you get energy M1 as energy M2, but there are many many more values for possible energy of the electron.

 

[Physicsissuef]

No!

a Beta particle = an electron; same thing but different name!

Each electron will only have ONE value of energy (M).

you must learn what a beta particle is.



No!

It just means that there is an equal probabilty that you get energy M1 as energy M2, but there are many many more values for possible energy of the electron.

I mean there are infinite possible kinetic energies for the electron, so there are infinite M points... Its the same, as you said...

 

[malawi_glenn]

I mean there are infinite possible kinetic energies for the electron, so there are infinite M points... Its the same, as you said...

Yes, but that was not what you wrote however.

 

[Physicsissuef]

Yes, but that was not what you wrote however.

And why did I said then? However, malawi_glenn, Astronuc and all others thank you very much for the help. Thanks again...

 

[malawi_glenn]

And why did I said then?

I don't understand you now.. please have a look at your spelling again.

My intention is not to mock you because of your bad english, I just want to know what you mean, it is very hard to understand some of the things that you write.

 

[Physicsissuef]

My real point was that there are infinite possible kinetic energies for the electron, so there are infinite M points, and probably the graphic is not correct... Sorry for any mistranslation...

 

[Physicsissuef]

the conclusion is that the graphic is partly correct, there are infinite M points.

 

[malawi_glenn]

the conclusion is that the graphic is partly correct, there are infinite M points.

the point that the graph wanted to make, was that each y-value is obtained by two x values. Execpt for the y_max which only one x value can give.

Compare with this function:

y(x) = -x^2+4.5*x on the interval: x from 0 to 4.5

on this interval, each y value can be obtained by two different x-values. y = 2.5 is given by x = 0,69 and 3,88. Only y_max = 5,06 which is given by x= 2.25

It is the same thing for the distribution functions for beta decay.

 

[Physicsissuef]

But didn't we said that there should be infinite M points, not only 2? MAybe the graphic want to say that the kinetic energy of the electrons is not constant?

 

[malawi_glenn]

Yes there are infinite many values for the energy!

But it was your counlcusion made in post #67 i reacted on.

The ultimate thing the graph wants to point out is that all the electrons are not emitted with the same energy, but the energy spans over a range. This is typical for a 3body decay - there are infinite number of combinate conservation of momentum and energy when you have more than 2 bodies in the final state.

You first question was about these M1 and M2, and that question has been answered severel times in this thread, each y-value have two corresponding x values, except y_max.

The Graphic is totaly correct.

 

[Physicsissuef]

Yes, we said that there are 2 corresponding values. But also we said that it can have 3,4,5,6,8,9,10000,10010... values for the kinetic energy of electrons...

 

[malawi_glenn]

Yes, we said that there are 2 corresponding values. But also we said that it can have 3,4,5,6,8,9,10000,10010... values for the kinetic energy of electrons...

So where is the graph not correct according to you?

 

[Physicsissuef]

I said it is correct... But having 2 points is not totally correct... It may confuse you, like in my case... I was confused why only 2 points, but later, thanks to you and Astronuc I understand that, actually there are infinite points (for each radionucleus, corresponding point, some points also may be same)...

 

[malawi_glenn]

Post #66 and 67 you say that is not correct, and only partly correct.

But anyway, I hope you have learned a bit how distribution functions work