Graduate Understanding Cantor set C in Ternary form with 1/n factor in front C

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The discussion revolves around understanding the Cantor set C in ternary form when modified by a factor of 1/n, where n is greater than or equal to 2. Participants express confusion over the notation "1/n C," questioning whether it means multiplying the set by 1/n or dividing it. Clarification is sought on how the Cantor set is constructed with this additional condition, particularly regarding the amount removed at each iteration. The conversation emphasizes the need for precise notation and a clearer explanation of the iterative process involved in creating the modified Cantor set. Ultimately, the thread highlights the complexities of mathematical notation and the importance of clear communication in discussing set theory concepts.
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I am trying to comprehend the Cantor set C with a 1/n factor in base 3
Dear Everybody,

I am confused by ##1/n C##, where C is a cantor set in base 3 and ##n\geq2##. I can understand the construction of the normal Cantor set.

How do I comprehend this set with this extra condition. Do I multiply the set with ##1/n## or not?

Thanks,
Cbarker1

mentor note: adjusted latex to use double # instead of single #
 
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cbarker1 said:
Understanding Cantor set C in Tetany form with 1/n factor in front C
I have never seen the word "Tetany" before: do you mean "ternery"? Even with this correction I'm afraid the rest of the post doesn't make much sense to me.

Do you have a reference for the ideas you are talking about?

If not, can you provide a more complete description of the set avoiding ambiguous notation like ##1/n C## which whether in ## \LaTeX ## or plain text can mean either ## \frac{1}{nC} ## or ## \frac{1}{n}C ##. Perhaps you could start by rephrasing "The Cantor ternary set is created by iteratively deleting parts of a set of line segments. One starts by deleting the open middle third ## \left ( \frac{1}{3} , \frac{2}{3} \right) ## from the interval ## [ 0 , 1 ] ##."
 
pbuk said:
have never seen the word "Tetany" before: do you mean "ternery"?
I changed "tetany" in the thread title to "ternary," as my best guess as to what the OP was trying to convey.

Also, perhaps the "1/nC" (with same complaint about what 1/nC actually means) is meant to convey the level of middle third deletions. Again, that's a guess. If so, with n = 1, we would have the two subintervals [0, .1] and [.2, 1], using base-3 fractions. With n =2, we remove the middle third from each of the two previously listed subintervals. This would produce four subintervals: [0, .01], [.02, .1], [.2, .21], and [.22, 1], again using base-3 fractions.

And so on.
 
Last edited:
your guesses are right. I want that word Ternary and ##(1/n)*C##.
 
OK, so how much of the set do you remove at the first iteration?

How much at the second?
...
How much at the ## n ##th?
...

How much in total as ## n \to \infty ##?
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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