Understanding Cantor set C in Ternary form with 1/n factor in front C

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    Cantor Form Set
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Discussion Overview

The discussion revolves around understanding a modified Cantor set denoted as ##1/n C##, where C is the standard Cantor set in base 3 and ##n \geq 2##. Participants explore the implications of this modification, particularly how the factor of ##1/n## affects the construction and interpretation of the Cantor set.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about the meaning of ##1/n C## and whether it involves multiplying the Cantor set by ##1/n## or some other interpretation.
  • Another participant questions the use of the term "Tetany," suggesting it may be a typo for "ternary," and highlights the ambiguity in the notation ##1/n C##, which could be interpreted in multiple ways.
  • A participant speculates that the notation might relate to the levels of middle third deletions in the Cantor set construction, providing examples for different values of ##n##.
  • Further clarification is sought regarding how much of the set is removed at each iteration and the total removal as ##n \to \infty##.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the interpretation of ##1/n C##, and multiple competing views regarding its meaning and implications remain present throughout the discussion.

Contextual Notes

There are unresolved ambiguities regarding the notation used, particularly the meaning of ##1/n C## and how it relates to the construction of the Cantor set. The discussion also reflects uncertainty about the specific details of the iterative removal process.

cbarker1
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TL;DR
I am trying to comprehend the Cantor set C with a 1/n factor in base 3
Dear Everybody,

I am confused by ##1/n C##, where C is a cantor set in base 3 and ##n\geq2##. I can understand the construction of the normal Cantor set.

How do I comprehend this set with this extra condition. Do I multiply the set with ##1/n## or not?

Thanks,
Cbarker1

mentor note: adjusted latex to use double # instead of single #
 
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cbarker1 said:
Understanding Cantor set C in Tetany form with 1/n factor in front C
I have never seen the word "Tetany" before: do you mean "ternery"? Even with this correction I'm afraid the rest of the post doesn't make much sense to me.

Do you have a reference for the ideas you are talking about?

If not, can you provide a more complete description of the set avoiding ambiguous notation like ##1/n C## which whether in ## \LaTeX ## or plain text can mean either ## \frac{1}{nC} ## or ## \frac{1}{n}C ##. Perhaps you could start by rephrasing "The Cantor ternary set is created by iteratively deleting parts of a set of line segments. One starts by deleting the open middle third ## \left ( \frac{1}{3} , \frac{2}{3} \right) ## from the interval ## [ 0 , 1 ] ##."
 
pbuk said:
have never seen the word "Tetany" before: do you mean "ternery"?
I changed "tetany" in the thread title to "ternary," as my best guess as to what the OP was trying to convey.

Also, perhaps the "1/nC" (with same complaint about what 1/nC actually means) is meant to convey the level of middle third deletions. Again, that's a guess. If so, with n = 1, we would have the two subintervals [0, .1] and [.2, 1], using base-3 fractions. With n =2, we remove the middle third from each of the two previously listed subintervals. This would produce four subintervals: [0, .01], [.02, .1], [.2, .21], and [.22, 1], again using base-3 fractions.

And so on.
 
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your guesses are right. I want that word Ternary and ##(1/n)*C##.
 
OK, so how much of the set do you remove at the first iteration?

How much at the second?
...
How much at the ## n ##th?
...

How much in total as ## n \to \infty ##?
 

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