Understanding Cantor set C in Ternary form with 1/n factor in front C

  • #1

cbarker1

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TL;DR Summary
I am trying to comprehend the Cantor set C with a 1/n factor in base 3
Dear Everybody,

I am confused by ##1/n C##, where C is a cantor set in base 3 and ##n\geq2##. I can understand the construction of the normal Cantor set.

How do I comprehend this set with this extra condition. Do I multiply the set with ##1/n## or not?

Thanks,
Cbarker1

mentor note: adjusted latex to use double # instead of single #
 

Answers and Replies

  • #2
Understanding Cantor set C in Tetany form with 1/n factor in front C
I have never seen the word "Tetany" before: do you mean "ternery"? Even with this correction I'm afraid the rest of the post doesn't make much sense to me.

Do you have a reference for the ideas you are talking about?

If not, can you provide a more complete description of the set avoiding ambiguous notation like ##1/n C## which whether in ## \LaTeX ## or plain text can mean either ## \frac{1}{nC} ## or ## \frac{1}{n}C ##. Perhaps you could start by rephrasing "The Cantor ternary set is created by iteratively deleting parts of a set of line segments. One starts by deleting the open middle third ## \left ( \frac{1}{3} , \frac{2}{3} \right) ## from the interval ## [ 0 , 1 ] ##."
 
  • #3
have never seen the word "Tetany" before: do you mean "ternery"?
I changed "tetany" in the thread title to "ternary," as my best guess as to what the OP was trying to convey.

Also, perhaps the "1/nC" (with same complaint about what 1/nC actually means) is meant to convey the level of middle third deletions. Again, that's a guess. If so, with n = 1, we would have the two subintervals [0, .1] and [.2, 1], using base-3 fractions. With n =2, we remove the middle third from each of the two previously listed subintervals. This would produce four subintervals: [0, .01], [.02, .1], [.2, .21], and [.22, 1], again using base-3 fractions.

And so on.
 
Last edited:
  • #4
your guesses are right. I want that word Ternary and ##(1/n)*C##.
 
  • #5
OK, so how much of the set do you remove at the first iteration?

How much at the second?
...
How much at the ## n ##th?
...

How much in total as ## n \to \infty ##?
 

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