Understanding Circular Motion: How Do Frequency, Radius, and Mass Relate?

Click For Summary
SUMMARY

This discussion focuses on the relationship between frequency, radius, mass, and centripetal force in circular motion, specifically using the equation Cf = 4(π²)mr(f²). The user seeks clarification on how to graph frequency against centripetal force, radius, and mass while keeping certain variables constant. The response emphasizes that when graphing, one can replace variables with x and y, allowing for flexibility in selecting constant values without affecting the graph's shape.

PREREQUISITES
  • Understanding of centripetal force and its equation
  • Familiarity with graphing techniques in physics
  • Knowledge of the relationship between frequency, radius, and mass
  • Basic algebra for manipulating equations
NEXT STEPS
  • Explore the derivation of the centripetal force equation Cf = 4(π²)mr(f²)
  • Learn how to graph equations involving multiple variables in physics
  • Investigate the impact of changing one variable while keeping others constant
  • Study the principles of harmonic motion and its relation to circular motion
USEFUL FOR

Students in physics courses, educators teaching circular motion concepts, and anyone interested in understanding the dynamics of frequency and centripetal force relationships.

KBrown
Messages
1
Reaction score
0
Hi. I would like to know if someone could help me out in this pre-lab homework.

Is only about theoretical x vs y graphics corelating frequency with radius, mass and centripetal force.

I have thhis equation, I am not sure if there are others that should be used, tough.

Cf=4([tex]\pi^2[/tex])mr([tex]f^2[/tex])

For the graphic f vs Cf Do I take in count radius and mass constant? Or do I just need antoher equation? Could you give it please?

For the graphic f vs r Do I take in count centripetal force and mass constant? Or is it with other equation?

For the f vs m graphic. Do I take in count radius and centripetal constant?


Thank you a lot.
 
Physics news on Phys.org
Welcome to the forum. A useful technique is to replace the variable in the equation by x and y. So the Cf vs f graph is x=A.m.r.y^2 ( A=4.pi^2) and the f vs Cf is y=A.m.r.x^2,
and so on. For anything that is not x or y, select a value that suits you.

The shape of the graph will not be affected by your choice, only the lengths of the axes.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
1K
Replies
2
Views
2K
Replies
55
Views
3K
Replies
1
Views
934
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 17 ·
Replies
17
Views
9K
Replies
6
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
6K