Understanding Circular Motion: The Importance of F=(mv^2)/r in Mass Spectrometry

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SUMMARY

The discussion centers on the application of the formula F=(mv^2)/r in the context of circular motion within mass spectrometry. Participants clarify that ions, once exiting the electric field, are influenced solely by the magnetic field, resulting in circular trajectories. The challenge lies in determining the radius (r) of the semicircular path that the ions take before impacting the detection plate. Understanding this relationship is crucial for accurate mass spectrometry analysis.

PREREQUISITES
  • Fundamentals of circular motion
  • Basic principles of mass spectrometry
  • Understanding of electric and magnetic fields
  • Knowledge of force equations in physics
NEXT STEPS
  • Research the derivation of F=(mv^2)/r in circular motion
  • Explore the role of magnetic fields in mass spectrometry
  • Learn how to calculate the radius of circular paths in physics
  • Investigate the impact of ion velocity on mass spectrometry results
USEFUL FOR

This discussion is beneficial for physics students, mass spectrometry researchers, and professionals involved in analytical chemistry who seek to deepen their understanding of the forces acting on ions in circular motion.

v_pino
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I managed to do part a) of the question but got stuck on b). Why use F=(mv^2)/r for circular motion? And even if I use this equation, how do I find r, the radius?

Thank you
PV
 

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When the ions leaves the electric field, they are only affected by the magnetic field and will therefor move in a circle. Altough they will only finnish half of the circle before they hit the plate. So, if you have a semicircle, where can you find the radius of the circle?
 
thanks :)
 

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