"Understanding Commuting Observables Proof

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SUMMARY

The discussion centers on the proof that two observables, denoted as \(\hat{O}\) and \(\hat{O}'\), commute if and only if they share a common basis of eigenvectors. The key equation presented is \((OO')_{jk}=\langle a_j|\hat{O}\hat{O}'|a_k\rangle=\sum_n\langle a_j|\hat{O}|a_n\rangle\langle a_n|\hat{O}'|a_k\rangle\). A participant expressed confusion regarding the indices in the final summation, questioning why it is \(\sum_n\hat{O}_{kn}\hat{O}'_{nj}\) instead of \(\sum_n\hat{O}_{jn}\hat{O}'_{nk}\). This was clarified as a typographical error, confirming the participant's intuition.

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  • Basic proficiency in linear algebra, particularly with summation indices.
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  • Study the properties of commuting operators in quantum mechanics.
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Students of quantum mechanics, particularly those beginning their studies, as well as educators seeking to clarify concepts related to observables and eigenvectors in quantum theory.

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Homework Statement



In the proof that two observables [tex]\hat{O}[/tex] and [tex]\hat{O}'[/tex] commute iff they admit a common basis of eigenvectors, I'm not understanding one part.

Homework Equations



If [tex]{|a_k\rangle}[/tex] is basis in Hilbert space we have:

[tex](OO')_{jk}=\langle a_j|\hat{O}\hat{O}'|a_k\rangle=\sum_n\langle a_j|\hat{O}|a_n\rangle\langle a_n|\hat{O}'|a_k\rangle=\sum_n\hat{O}_{kn}\hat{O}'_{nj}[/tex]


Now I'm confused a bit. And maybe I'm not understanding the matter that well (I'm only starting to study QM), but why is the last part

[tex]\sum_n\hat{O}_{kn}\hat{O}'_{nj}[/tex] and not [tex]\sum_n\hat{O}_{jn}\hat{O}'_{nk}[/tex]?

I mean it 'feels' to me that the latter should be true, because it is in the brackets (I mean the indices)...
 
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You're right. The indices are messed up in the last step.
 
Oh, so it's a typing error... Well that's yay! for me (this time my intuition wasn't wrong ^^)
 

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