Understanding Current Sense in Circuits: The Reversal Dilemma

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SUMMARY

The discussion centers on the concept of current direction in circuits, specifically regarding the current ib through an 11Ω resistor, which is given as -2A. The solutions manual reverses the current direction to 2A flowing from left to right, adhering to the conventional flow of current from positive to negative terminals. The negative sign indicates that the current is indeed flowing in the reverse direction, confirming that both approaches can yield valid results as long as the sign convention is properly applied.

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sevag00
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Hi. It's me again with another confusing circuit problem. The first attached image below shows ib going from right to left through the 11Ω resistor and ib is given -2A. In the solutions manual of the book, it has reversed the direction of the current as in going from left to right and taken the value 2A.
My questions is, why has the solutions manual reversed the direction and not just solved it from left to right and taking the current -2A? Could it be solved it both ways?
 

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The current always flows from +ve terminal to -ve. The negetive sign just indicates that current is positive in the reverse direction (in other words it is flowing in the reverse direction). Since ib is given as -2A it is saying that the current is 2A in the reverse direction (which is indicated in the solution manual). It could be solved in both ways. Just keep in mind the sign convention.
Regards
 
Aha. Thanks for the answer.
 

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